Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of
. So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Answer:
(-2, -5)
(-1, -2)
(0, 1)
(1, 4)
(2, 7)
Step-by-step explanation:
Substitute x with each number and solve equation.
Answer:
<u>Here is ur answer </u><u>:</u>
1. Probability of composing music for a movie is 1
2. To choose the group in 11 th grade , choosing the subject in which it's more probable to score high marks .
3. To decide whether to go out in rain , the probability of getting cold is more than enjoying the rain .
4. Sorry i don't know
Hope the others will help you !!
The mistake is “there are”
Answer:
5x + 6y = -10
Step-by-step explanation:
(-2, 0) and (-8, 5)
m = (y₂ - y₁) / (x₂ - x₁)
m = (5 - 0) / (-8 -(-2)
m = 5 / (-8+2)
m = -5/6
y = mx + b
(-8, 5)
5 = -5/6(-8) + b
5 = 40/6 + b
b = 5 - 40/6
b = -5/3
y = mx + b
y = -5/6x - 5/3 *6
6y = -5x -5(2)
6y = -5x - 10
5x + 6y = -10