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Vsevolod [243]
3 years ago
8

Anyone know the answer to this

Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0
There are 180 Degrees in a triangle, you know two, 90 and 79, so the last angle is 11
180-90-79=11
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What is the value if the expression 6+18÷3×4
Liula [17]
In the order of PEMDAS
the first thing you would do is divide 18/3 = 6
then multiply 6 x 4 = 24
then add 24 + 6 = 30
8 0
3 years ago
Read 2 more answers
Solve for the value of v: V+27=117
Fudgin [204]
V+27=117
Subtract 27 to 117:
v=90
7 0
2 years ago
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The potential energy of an object varies jointly with the mass of the object and the height of the object off the ground. A 25-k
xxMikexx [17]

Answer:

This is physics. By the way look the explanation.

Step-by-step explanation:

The formula of Potential Energy is E=mgh, where m is the mass of the object, g the gravitational, and h the height of the object. Given that the potential energy of the object is 150 Joules at 3 meters height, Represent m=E/(g*h), considering g=9.8 m/s^2(Because this value was used for the first object), we get m=150/9.8/3=5.102

Rounding to 2 decimals` 5.10 kg

4 0
3 years ago
Read 2 more answers
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
I need help with this question pleaseeee
Softa [21]

Answer: 639

Step-by-step explanation:

i might be wrong but that's how i was taught! :)

8 0
3 years ago
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