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kvasek [131]
3 years ago
14

Solve for c 1.2c = 0.6

Mathematics
2 answers:
Elodia [21]3 years ago
8 0

1.2c=0.6

Divide both sides by 1.2

1.2c/1.2=0.6/1.2

c= 0.5


Check the answer

Replace c by its number

1.2*0.5=0.6

0.6=0.6

So the answer is good


I hope that's help !

suter [353]3 years ago
4 0
1.2c=0.6
you have to divide 1.2 on both sides. 0.6/1.2=1/2
c=1/2 
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△ABC ≅ △DEF, EF = x 2 - 7, and BC = 4x - 2.
Artist 52 [7]

Answer:

Therefore the value of x is 5.

Step-by-step explanation:

Given:

△ABC ≅ △DEF,

EF = x 2 - 7, and

BC = 4x - 2.

To Find:

the values of x. = ?

Solution:

△ABC ≅ △DEF      ........Given

If two Triangles are congruent then the Corresponding Parts of Congruent Triangles are Congruent.

∴ BC ≅ EF   ...................CPCTC

Substituting the values we get

4x-2=x^{2}-7\\x^{2}-4x-5=0

Now By Factorizing we get

x^{2}-5x+x-5=0\\x(x-5)+1(x-5)=0\\(x+1)(x-5)=0\\x+1=0\ or\ x-5=0\\x=-1\ or\ x=5\\x\ cannot\ be\ negative\\\therefore x=5

Therefore the value of x is 5.

8 0
3 years ago
The augmented matrix of a system of equations has been transformed to an equivalent matrix in​ row-echelon form. Using​ x, y
jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

  • There is a row of all zeros at the bottom of the matrix;
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For this question, the matrix is a Row Echelon Form and is written as:

\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]

or in system form:

x + 2y + 2z = 4

       y + 3z = 9

               z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0
3 years ago
I need help with these 2 questions please help me with scie
Andre45 [30]
He's using the graduated cylinder method. I think the volume might be between 15 and 20. (It's kind of not obvious...)
3 0
2 years ago
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Anarel [89]
For the first one write 9 divided by 2 gives your your radius an it’s 3.5. the formula is 2 x 3.14 x radius and that gives you 21.98.

the 2nd one is 2 x 3.14 x 9 = 56.52

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3 0
1 year ago
Read 2 more answers
Let L be the line parametrized by x = 2 + 2t, y = 3t, z = −1 − t. (a) Find a linear equation for the plane that is perpendicular
Elden [556K]

Answer:

Step-by-step explanation:

Given that L is a line parametrized by

x = 2 + 2t, y = 3t, z = −1 − t

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z

i.e. (2,3,-1)

So equation of the plane would be of the form

2x+3y-z =K

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

2(2)+3(0)-(-1) =K\\K =5

So equation is

2x+3y-z =5

b) Substitute general point of L in the plane to find the intersecting point

2(2+2t)+3t-(-1-t) =5\\4+8t+1=5\\8t=0\\t=0\\(x,y,z) = (2,0,-1)

i.e. same point given.

3 0
3 years ago
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