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cupoosta [38]
3 years ago
10

What basic trigonometric identity would you use to verify that sin^2x +cos^2x/cos x = sec x

Mathematics
1 answer:
gogolik [260]3 years ago
6 0

<u>Answer:</u>

The basic identity used is \bold{\sin ^{2} x+\cos ^{2} x=1}.

<u>Solution: </u>

In this problem some of the basic trigonometric identities are used to prove the given expression.

Let’s first take the LHS:

\Rightarrow \frac{\sin ^{2} x+\cos ^{2} x}{\cos x}

Step one:

The sum of squares of Sine and Cosine is 1 which is:

\sin ^{2} x+\cos ^{2} x=1

On substituting the above identity in the given expression, we get,

\Rightarrow \frac{\sin ^{2} x+\cos ^{2} x}{\cos x}=\frac{1}{\cos x} \rightarrow(1)

Step two:

The reciprocal of cosine is secant which is:

\cos x=\frac{1}{\sec x}

On substituting the above identity in equation (1), we get,

\Rightarrow \frac{\sin ^{2} x+\cos ^{2} x}{\cos x}=\sec x

Thus, RHS is obtained.

Using the identity \sin ^{2} x+\cos ^{2} x=1, the given expression is verified.

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At a price of $p the demand x per month (in multiples of 100) for a new piece of software is given by x 2 + 2xp + 4p 2 = 5200. B
WINSTONCH [101]

Answer:

The rate of decrease in demand for the software when the software costs $10 is -100

Step-by-step explanation:

Given the function of price $p the demand x per month as,

x^{2}+2xp+4p^{2}=5200

Also given that, the price is increasing at the rate of 70 dollar per month.

\therefore \dfrac{dp}{dt}=70.

To find rate of decrease in demand, differentiate the given function with respect to t as follows,

\dfrac{d}{dt}\left(x^2+2xp+4p^2\right)=\dfrac{d}{dt}\left(5200\right)

Applying sum rule and constant rule of derivative,

\dfrac{d}{dt}\left(x^2\right)+\dfrac{d}{dt}\left(2xp\right)+\dfrac{d}{dt}\left(4p^2\right)=0

Applying constant multiple rule of derivative,

\dfrac{d}{dt}\left(x^2\right)+2\dfrac{d}{dt}\left(xp\right)+4\dfrac{d}{dt}\left(p^2\right)=0

Applying power rule and product rule of derivative,

2x^{2-1}\dfrac{dx}{dt}+2\left(x\dfrac{dp}{dt}+p\dfrac{dx}{dt}\right)+4\left(2p^{2-1}\right)\dfrac{dp}{dt}=0

Simplifying,

2x\dfrac{dx}{dt}+2\left(x\dfrac{dp}{dt}+p\dfrac{dx}{dt}\right)+8p\dfrac{dp}{dt}=0

Now to find the value of x, substitute the value of p=$10 in given equation.

x^{2}+2x\left(10\right)+4\left(10\right)^{2}=5200

x^{2}+20x+400=5200

Subtracting 5200 from both sides,

x^{2}+20x+400-5200=0

x^{2}+20x-4800=0

To find the value of x, split the middle terms such that product of two number is 4800 and whose difference is 20.

Therefore the numbers are 80 and -60.

x^{2}+80x-60x-4800=0

Now factor out x from x^{2}+80x and 60 from 60x-4800

x\left(x+80\right)-60\left(x+80\right)=0

Factor out common term x+80,

\left(x+80\right)\left(x-60\right)=0

By using zero factor principle,

\left(x+80\right)=0 and \left(x-60\right)=0

x=-80 and x=60

Since demand x can never be negative, so x = 60.

Now,

2x\dfrac{dx}{dt}+2\left(x\dfrac{dp}{dt}+p\dfrac{dx}{dt}\right)+8p\dfrac{dp}{dt}=0

Substituting the value.

2\left(60\right)\dfrac{dx}{dt}+2\left(60\left(70\right)+10\dfrac{dx}{dt}\right)+8\left(10\right)\left(70\right)=0

Simplifying,

120\dfrac{dx}{dt}+2\left(4200+10\dfrac{dx}{dt}\right)+5600=0

120\dfrac{dx}{dt}+8400+20\dfrac{dx}{dt}+5600=0

Combining common term,

140\dfrac{dx}{dt}+14000=0

Subtracting 14000 from both sides,

140\dfrac{dx}{dt}=-14000

Dividing 140 from both sides,

\dfrac{dx}{dt}=-\dfrac{14000}{140}

\dfrac{dx}{dt}=-100

Negative sign indicates that rate is decreasing.

Therefore, the rate of decrease in demand of software is -100

6 0
3 years ago
The number of eggs in the refrigerator e decreased by 9 equals 17.
alexandr402 [8]

Answer:

x-9=17

Step-by-step explanation:

x=eggs in the fridge

5 0
3 years ago
Identify the diameter of the disc
Olegator [25]

radius = (4*10^2 + 24^2)/8*10 =

(400 + 576)/80=

976/80 = 12.2

diameter = 12.2 x 2 = 24.4

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3 years ago
Which could be the running speed of a human in meters per second?
kvv77 [185]
1 x 10. It is unlikely that someone will run 103 meters in a second, along with 1010.
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What's the equation for this problem? Please help!! It's due tomarrow
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Wth diaiqowjqksosjshbssbbsjsoaiajw
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