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Westkost [7]
3 years ago
12

In humans, male-pattern baldness may be assumed to be controlled by an autosomal gene that occurs in two allelic forms. Allele B

determines nonbaldness, and allele b determines pattern baldness. In males, because of the presence of testosterone, allele b is dominant over B. If a man and woman both with genotype Bb have a son, what is the chance that he will eventually be bald?
Biology
1 answer:
kirza4 [7]3 years ago
5 0

Answer:

75% of chance that their son would be bold

Explanation:

Doing a Punnet square, you can determine the chances that have the F1 whit certain characteristics.  

In a Punnet square, the capital letter represents a dominant characteristic, and the lower case letter represents a recessive characteristic. But in this case, because of the presence of testosterone, allele b is dominant over B.  Dominant mens that if is a pair of heterozygous chromosom, the dominant will appear in the phenotype, means physically. The recessive characteristic will prevail but only in the genotype

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