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Mariulka [41]
4 years ago
12

7.38 is a mixed decimal. True or false

Mathematics
2 answers:
Nadya [2.5K]4 years ago
8 0
Noup..
It's false 
The number mixed are like ↓↓this one↓↓

Blababa [14]4 years ago
3 0

Answer:

Step-by-step explanation:

True

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Find the product of 3,000 and 9.
Advocard [28]
3,000 x 9 = 27,000
The answer would be A
4 0
4 years ago
Help pls!!!! I would really appreciate your help :)
IgorC [24]

Answer:

1921579

Step-by-step explanation:

We can work this out by simply plugging the given value 2 into the functions in ascending order:

G(2) = 3(2) - 11\\= 6 - 11\\= -5

F(-5) = 2(-5)^2 + 4(-5) + 10\\= 2 * 25 - 20 + 10\\= 50 - 20 + 10\\= 40

H(40) = 3(40)^3 + 40^2 - 21\\= 3 * 64000 + 1600 - 21\\= 192000 + 1600 - 21\\= 1921579

7 0
4 years ago
Which of the following statements properly define a variable? Select all that apply. a. Let w represent Enrique's weight b. Let
RoseWind [281]

Answer: c. Let d represent Enrique's distance from home (in miles).

e. Let w represent Enrique's weight in pounds

Step-by-step explanation:

A variable is a particular type of value that denotes an unknown quantity.

  • It is denotes by using alphabets.
  • It can change.

To define a variable , we need define a amount or quantity with units and in case of length an exact position is required.

a. Let w represent Enrique's weight

It is not a variable because no units is defined.

b. Let d represent Enrique's distance (in miles).

It is not a variable because the points to establish distance traveled by Enrique is not given .

c. Let d represent Enrique's distance from home (in miles).

It is a variable as both units and position as mentioned.

d. Let d represent Enrique's distance from home.

It is not a variable because no units is defined.

e. Let w represent Enrique's weight in pounds.

It is a variable because unit of weight is mentioned.

Hence, the correct statements that properly define a variable are  :

c. Let d represent Enrique's distance from home (in miles).

e. Let w represent Enrique's weight in pounds

4 0
4 years ago
Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.​
Dimas [21]

Answer:

The nonzero value of c will be:

  • c = 6

Step-by-step explanation:

Given the function

f\left(x\right)=\:x^2-4x-c

f\left(c\right)=\:c^2-4c-c

as

f(c) = c

so

c=\:c^2-4c-c

switching the sides

c^2-4c-c=c

subtract c from both sides

c^2-4c-c-c=c-c

c^2-6c=0

c\left(c-6\right)=0

Using the zero factor principle

\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

c=0\quad \mathrm{or}\quad \:c-6=0

so, the solutions to the quadratic equations are:

c=0,\:c=6

Therefore, a nonzero value of c will be:

  • c = 6
5 0
3 years ago
Where did the word algebra originate from originally
prohojiy [21]
The word algebra originate from baghdad. 
3 0
3 years ago
Read 2 more answers
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