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Readme [11.4K]
3 years ago
8

Simplify the following algebraic expression -9-10[7x-3(3+10x)]

Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0
<span>-9 -10[7x -3(3 + 10x)]

= -9 - 10(7x - 9 - 30x)

= -9  - 10( -23x - 9)

= -9 + 230x + 90

= 230x + 81

Answer: </span>230x + 81<span>

</span>
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Bonita evaluated 5/6 × 1 2/3 and got an answer of 7/3. How can you tell that her answer is wrong?
Free_Kalibri [48]
C is the answer to the problem
7 0
4 years ago
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If f(x)=2x^3−x^2−16x+15 and f(−3)=0, list all of the zeros from least to greatest
goblinko [34]

The roots from smallest to greatest are -3, 1, and 5/2 or (2 1/2).

7 0
3 years ago
The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12
Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

P(x)=-12x^2+120x

To find:

The current that will produce the maximum power.

Solution:

We have,

P(x)=-12x^2+120x

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

In the given function, a=-12 and b=120. So,

-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}

-\dfrac{b}{2a}=-\dfrac{120}{-24}

-\dfrac{b}{2a}=5

Putting x=5 in the given function, we get

P(5)=-12(5)^2+120(5)

P(5)=-12(25)+600

P(5)=-300+600

P(5)=300

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0
3 years ago
Which equation can be used to determine what number, n, is 40% of 64?
11111nata11111 [884]
Of means multiply, so it would be 40% x 64
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3 0
4 years ago
Pls help<br><br> Solve for x. 6x/4 −24=x−2
riadik2000 [5.3K]

Answer:

6x/4-24=x-2

6x/4-24/1=x-2

(6x/4)1-(24/1)4=x-2

6x/4-96/4=x-2

(6x-96)/4=(x-2)/1

Then cross multiply to get this;

(6x-96)1=(x-2)4

6x-96=4x-8

6x-96+96=4x-8+96

6x=4x+88

6x-4x=4x-4x+88

2x=88

Divide both sides by 2

2x÷2=88÷2

x=44

Thank you.

BY GERALD GREAT.

5 0
3 years ago
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