Answer:
To get system B, the SECOND equation in system A was replaced by the sum of that equation and the FIRST equation multiplied by FOUR. The solution to system B IS de same as the solution to system A
Step-by-step explanation:
x-y=3 equation 1
-2x+4y=-2 equation 2
so, multiplying by four the equation 1 we have
4x-4y=12 equation 3
later sum equation 3 and equation 2 we have
2x=10
Answer:
nx^(n-1).
Step-by-step explanation:
d/dx (x^n)
We multiply by n than subtract 1 from the exponent (n):
= n x^(n-1)
Numerical examples:
d(x^3) dx = 3 * x^(3-1)
= 3x^2.
d(2x^5)/dx = 5*2 x^(5-1)
= 10x^4.
Answer:
50 minutes
Step-by-step explanation:
it takes 80 minutes for 5 pipes
so for 1 pipe it will take 5x80=400min
and for 8 pipes it will take 400/8=50min
Step-by-step explanation:
![2 ^{ \frac{1}{2} } = 2 ^{1 \times \frac{1}{2} } = \sqrt{2} \\ {2}^{ \frac{2}{3} } = 2 ^{2 \times \frac{1}{3} } = \sqrt[3]{2 ^{2} } \\ 3 ^{ \frac{3}{2} } = {3}^{3 \times \frac{1}{2} } = \sqrt[]{ {3}^{3} } \\ {3}^{ \frac{1}{3} } = 3 ^{1 \times \frac{1}{3} } = \sqrt[3]{3}](https://tex.z-dn.net/?f=2%20%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%3D%202%20%5E%7B1%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B2%7D%20%20%5C%5C%20%20%7B2%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%20%3D%202%20%5E%7B2%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B2%20%5E%7B2%7D%20%7D%20%20%5C%5C%203%20%5E%7B%20%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%3D%20%20%7B3%7D%5E%7B3%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%5B%5D%7B%20%7B3%7D%5E%7B3%7D%20%7D%20%20%5C%5C%20%20%7B3%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%203%20%5E%7B1%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B3%7D%20)
You will do area for a triangle . when multiplying with the (x+9) you will just multiply the number infront of the parentheses by both the x and the 9. for example the 60 would be 60(x+9) which would be 60x+540
