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2 years ago

What is the most common data link layer protocol for a wired connection

2 answers:

6 0

The common data link layer protocol for wired connection is point to point protocol (PPP) Which is a data link layer communication protocol used to establish a direct connection between two nodes.It connects two routers directly without any host or any other networking device in between.This protocol is used for a very basic level of connectivity providing data linkage between the computers.It is widely used for the heavier and faster connections necessary for broadband communications.

krek1111 [17]2 years ago

4 0

I think the answer is The PPP (Point-to-Point Protocol). 

It is the most common type of protocol that people use using a modem, a device or a router to have an internet connection. Here there two systems that establish a link to each other which is the point to point. The bits are transferred to a sender and a receiver.

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You have several marketing documents that are published through AD RMS. However, you have three new marketing employees that req

snow_lady [41]

Answer:

Document unauthorized

Explanation:

this way new employees will not try to open

5 0

3 years ago

During the boot process, the computer performs a quick self diagnostic then loads the operating system into memory.... IS THIS T

zlopas [31]

The answer is False. During the boot process, the computer will perform a self-diagnostic, also known as a POST and load necessary drivers and programs that help the computer and devices communicate.

7 0

2 years ago

P16 Consider the following network. ISP B provides national backbone service to regional ISP A. ISP C provides national backbone

Art [367]

Solution :

Considering the following data :

$\text{ISP B}$ provides the national backbone to the regional $\text{ISP A}$ .

$\text{ISP C}$ provides the national backbone to the regional $\text{ISP D}$ .

Each of the ISP consists of one autonomous systems (AS).

$\text{ISP B}$ would like to hand over the traffic of C through the $\text{West}$ Coast.

The $\text{ISP C}$ would like to receive traffic from B's peering point via East Coast.

One way for $C$ to force $B$ to hand over all of $B$ ’s traffic to $D$ on the east coast is for $C$ to only advertise its route to $D$ via its east coast peering point with $C$ .

7 0

2 years ago

Understanding Sequential Statements Summary

Kisachek [45]

Answer:

// Payroll.java

public class Payroll

{

int numOfDependents;

double salary;

double salaryToHome;

double Federal_Tax,TAX_RATE,Depen_tax;

Payroll(double salry,int nod)

{

numOfDependents=nod;

salary=salry;

Federal_Tax=6.5;

TAX_RATE=28.0;

Depen_tax=2.5;

}

double getTAX_RATE()

{

return TAX_RATE*salary/100;

}

double Federal_Tax()

{

return Federal_Tax*salary/100;

}

double getDepenAmount()

{

return numOfDependents*(Depen_tax*salary/100);

}

double getTakeHomeSalary()

{

return salary+getDepenAmount()-(getTAX_RATE()+Federal_Tax());

}

void printOutput()

{

System.out.print("\nState Tax: $"+getTAX_RATE());

System.out.print("\nFederal Tax: $"+Federal_Tax());

System.out.print("\nDependents: $"+getDepenAmount());

System.out.print("\nSalary: $"+salary);

System.out.println("\nTake Home Pay: $"+getTakeHomeSalary());

}

public static void main(String args[])

{

Payroll obj=new Payroll(1250,2);

obj.printOutput();

}

// ModifiedPayroll.java

import java.util.Scanner;

public class ModifiedPayroll

{

int numOfDependents;

double salary;

double salaryToHome;

double Federal_Tax,TAX_RATE,Depen_tax;

ModifiedPayroll(double salry,int nod)

{

//initialise variables

numOfDependents=nod;

salary=salry;

Federal_Tax=6.5;

TAX_RATE=28.0;

Depen_tax=2.5;

}

double getTAX_RATE()

{

return TAX_RATE*salary/100;

}

double Federal_Tax()

{

return Federal_Tax*salary/100;

}

double getDepenAmount()

{

return numOfDependents*(Depen_tax*salary/100);

}

double getTakeHomeSalary()

{

return salary+getDepenAmount()-(getTAX_RATE()+Federal_Tax());

}

void printOutput()

{

System.out.print("\nState Tax: $"+getTAX_RATE());

System.out.print("\nFederal Tax: $"+Federal_Tax());

System.out.print("\nDependents: $"+getDepenAmount());

System.out.print("\nSalary: $"+salary);

System.out.println("\nTake Home Pay: $"+getTakeHomeSalary());

}

public static void main(String args[])

{

Scanner sc=new Scanner(System.in);

System.out.print("\nEnter Salary: $");

double salary=sc.nextDouble();

System.out.print("\nEnter number Of Dependents:$");

int nob=sc.nextInt();

ModifiedPayroll obj=new ModifiedPayroll(salary,nob);

obj.printOutput();

}

Explanation/Output:

// For Payroll.java

State Tax: $350.0

Federal Tax: $81.25

Dependents: $62.5

Salary: $1250.0

Take Home Pay: $881.25

// For ModifiedPayroll.java

Enter Salary:$1550.0

Enter number of Dependents:$3

State Tax: $434.0

Federal Tax: $100.75

Dependents: $116.25

Salary: $1550.0

Take Home Pay: $1131.5

8 0

3 years ago

Assume inputFile is a Scanner object used to read data from a text file that contains a number of lines. Each line contains an a

anzhelika [568]

Answer:

words.hasNext()

Explanation:

Given the code snippet below:

while (inputFile.hasNextLine()) {
String word = "";
String line = inputFile.nextLine();
Scanner words = new Scanner(line);
while (words.hasNext()) {
word = words.next();
}
System.out.println(word); }
}

We have a inputFile Scanner object that can read data from a text file and we presume the inputFile has read several rows of data from the text file. So long as there is another line of input data available, the outer while loop will keep running. In each outer loop, one line of data will be read and assign to line variable (Line 3). Next, there is another Scanner object, words, which will take the current line of data as input. To get the last word of that line, we can use hasNext() method. This method will always return true if there is another tokens in its input. So the inner while loop will keep running so long as there is a token in current line of data and assign the current token to word variable. The word will hold the last token of current line of data upon exit from the inner loop. Then we can print the output (Line 8) which is the last word of the current line of data.

7 0

3 years ago