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jeka57 [31]
3 years ago
9

Carmen is making gift boxes for her friends. It takes her 10 minutes to pack a 4-pound treat box, and it takes her 15 minutes to

pack a 2-pound game box. Carmen wants to spend no more than 100 minutes packing boxes, and she can only carry up to 50 pounds in her car.
This graph and system of inequalities represent this situation, where x represents the number of treat boxes and y represents the number of game boxes.
10x + 15y ≤ 100
4x + 2y ≤ 50
Mathematics
1 answer:
Darya [45]3 years ago
4 0

Answer:

(5.2) for sure

Step-by-step explanation:

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My friend and I have different calling plans. Mine has a monthly fee of $10 and $0.08 per minute charge. My friend pays $0.06 a
loris [4]

difference is monthly customer fee= 15-10 = $5

difference in minutely charge = 0.08-0.06 = $0.02

minutes it takes for plans to cost same amount= 5÷0.02 = 250 min

7 0
4 years ago
Mrs Lefatshe bought 15 metres of cloth.the cost of 1 metre is P69.95. how much did she have to pay?​
irina1246 [14]

Answer:

1042.5

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • Mrs Lefatshe bought 15 metres of cloth.the cost of 1 metre is P69.95 .

<u>Using </u><u>Unitary</u><u> Method</u><u> </u><u>:</u><u>-</u><u> </u>

→ Cost of 1 m is P 69.95

→ Cost of 15m is P ( 69.5 * 15 ) = P 1042.5

6 0
3 years ago
Drako found an emerald in a cave at a depth between Negative one-half and Negative 1 and two-thirds meters. Which number could r
8090 [49]

Options :

Negative 2 and one-third meters

Negative three-fourths meters

Negative one-fourth meters

Negative 1 and

StartFraction 5 Over 6 EndFraction meters

Answer: Negative three-fourths meters

Step-by-step explanation:

Given the following :

Depth Location of Emerald :

Between - 1/2 and - 1 2/3

The answer will be the option which lies between the two depth points.

-1/2 = - 0.5 ( upper bound)

-1 2/3 = - 1.667 ( lower bound)

The option which lies inbetween :

- 1.667 and - 0.5

Taking each option :

Negative 2 and one-third meters = - 2 1/3 = - 2.33

Negative three-fourths meters = - 3/4 = - 0.75

Negative one-fourth meters = - 1/4 = - 0.25

Negative 1 and StartFraction 5 Over 6 EndFraction meters = - 1 5/6 = - 1.833

Hence, the only depth position which lies inbetween (-1.667 and - 0.5) is - 0.75

4 0
3 years ago
Read 2 more answers
A map has a scale of 1/2 inch= 20miles quinn wants to travel an actual distance
inessss [21]

Answer:

1.75 inches or 1 3/4inches

Step-by-step explanation:

A map has a scale of ½½inch=20mles. Quinn wants to travel an actual distance of 70miles. What will the length on the map be?

70/20

=7/2

=1/2×7/2

=7/4

=1 3/4 inches

in decimal its 1.75 inches

5 0
2 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.60.6 times per day. What is the probability tha
OLEGan [10]

Answer:

0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 per day.

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash more than 3 times?

Either it crashes 3 or less times, or it crashes more than 3 times. The sum of the probabilities of these events is decimal 1. So

P(X \leq 3) + P(X > 3) = 1

We want P(X > 3). So

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

P(X = 3) = \frac{e^{-4.2}*(4.2)^{3}}{(3)!} = 0.1852

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0150 + 0.0630 + 0.1323 + 0.1852 = 0.3955

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.3955 = 0.6045

0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.

3 0
4 years ago
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