Answer: y=-2x-9
Step-by-step explanation:
If ANGL is a square, then NG and LG are adjacent sides.
Adjacent sides are perpendicular. [Each angle is 90°]
The equation of line NG is 
.
By comparing it to equation in slope intercept form y=mx+c ( where , m= slope , c=y-interecpt)
slope =
Let slope of LG be <em>n</em>, then
[Product of slopes of two perpendicular line =-1]
Equation of a line passes through (a,b) and have slope m is given by :-
Equation of LG :
[In intercept form]
Answer:
Step-by-step explanation:
The relative speed of the two trains is the sum of the speeds they are traveling. (If you're on either of the trains, this is the speed you appear to be moving when you see the other train.) In our problem, the relative speed of the two trains is 70 mph + 60 mph = 130 mph. What if the trains were traveling in the same direction? Then we'd need to subtract the speed of the slower train from the speed of the faster train, and their relative speed would be 10 mph.
Answer:
$69.17
Step-by-step explanation:
.065 x 64.95 ≈ $4.22
$69.17 + $4.22 = $69.17
Brainliest would be appreciated but not required :)
Answer:
h = (24 - 3x - x²)/(2x + 3)
Step-by-step explanation:
Surface area:
2(x × (x + 3)) + 2(x)h + 2(x + 3)h
2(x² + 3x) + 2xh + 2(x + 3)h = 48
x² + 3x + xh + xh + 3h = 24
h(2x + 3) = 24 - x² - 3x
h = (24 - 3x - x²)/(2x + 3)
Answer:
linear
Step-by-step explanation:
