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kari74 [83]
2 years ago
14

Write an expression for the perimeter of the triangle shown below

Mathematics
2 answers:
Luba_88 [7]2 years ago
7 0

Answer:

P = 5.5x + 9

Step-by-step explanation:

P = 5x + (0.3x + 24) + (0.2x - 15)

reduced

P = 5.5x + 9

Nadusha1986 [10]2 years ago
6 0
P=5.5+9 hope this helps :)
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Find the interval in which f(x)=sinx−cosx is increasing or decreasing?
alisha [4.7K]

Answer:

There is no short answer.

Step-by-step explanation:

To find to intervals which f(x) increases or decreases, we first need to find it's derivative.

f(x) = sinx - cosx\\f'(x) = cosx - (-sinx) = cosx + sinx

The function is increasing when it's value is  > 0 and decreasing when it's value is < 0.

If we take a look at this graph, cosx+sinx is positive when they are both positive or when cosx is greater then sinx on the negative part.

I hope this answer helps.

3 0
3 years ago
Find the value of b.<br> 15°<br> 25°<br> bº<br> b=
kvv77 [185]

Answer:

35

Step-by-step explanation:

15 plus 10 equals 25.

25 plus 10 equals 35.

Hope it helps!

7 0
3 years ago
I think of a number add 3 to it and multiply the results by 6 ​
Ann [662]

Answer:45

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Convert 0.00049 to scientific notation.
SOVA2 [1]
It's 10 - 4

moving decimal over to the right makes a negative exponent.
7 0
3 years ago
Read 2 more answers
A) Dos números enteros positivos se diferencian en 6 unidades y la suma de sus cuadrados
lianna [129]

Queremos encontrar dos números enteros tales que su diferencia sea de 6 y la suma de sus cuadrados sea igual a 260.

Veremos que los dos números son 8 y 14.

Primero, podemos definir esos números como A y B.

Entonces tenemos que:

A - B = 6

A^2 + B^2 = 260

Esto es un sistema de ecuaciones.

Para resolverlo, el primer paso es aislar una de las variables en una de las ecuaciones, vamos a hacer esto en la primera.

A - B = 6

A = 6 + B

Ahora reemplazamos esto en la otra ecuación.

A^2 + B^2 = 260

(6 + B)^2 + B^2 = 260

36 + 12*B + B^2 + B^2 = 260

36 + 12*B + 2*B^2 = 260

Ahora podemos resolver esto para B:

2*B^2 + 12*B + 36 - 260 = 0

2*B^2 + 12*B - 224

Las soluciones estan dadas por la formula de Bhaskara:

B = \frac{-12\pm \sqrt{12^2 - 4*2*(-224)} }{2*2} \\\\B =  \frac{-12 \pm 44 }{4}\\\\B =  (-3 \pm 11)

Entonces las dos soluciones son:

B = -3 + 11 = 8

B = -3 - 11 = -14

Sabemos que los números son positivos, asi que elejimos la primera, entonces tenemos:

B = 8.

Con esto podemos calcular el valor de A como:

A - B = 6

A = 6 + B = 6 + 8 = 14

Entonces los dos números son:

8 y 14.

Si deseas aprender más, puedes leer:

brainly.com/question/24761554

6 0
2 years ago
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