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Lorico [155]
4 years ago
5

Will give brainliestt

Mathematics
2 answers:
s344n2d4d5 [400]4 years ago
4 0
From Venn diagram, we can see that

4 own both car and truck.

15 own car exclusively.

9 own truck exclusively.

So now there are 36 people in total so that would be 36 - 15 - 4 - 9 = 8 people who do not own anything


So far we have
4    9   _
15  8   _
_    _   _

Now we just need to fill in remaining blanks

We know that there are 4 + 9 = 13 people who owns truck regardless of car

Also there are 15 + 8 = 23 people who does not own trucks regardless of car

Now 13 + 23 = 36 so math checks.

Now for car, we can see that there are 4 + 15 = 19 people who owns car regardless of trucks

Now there are 9 + 8 = 17 people who does not own car regardless of trucks.

19 + 17 = 36 so math checks again.

So table should look like this:

4     9    13
15   8    23
19   17  36
Ann [662]4 years ago
4 0

Answer:

just took the test! Here is the answer for anyone else wondering:

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if your adding more stuff to your shopping cart it does not matter what item it is it will always increase  

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Suppose you have a box with 3 blue marbles, 2 red marbles, and 4 yellow marbles. You are going to pull out one marble, record it
balandron [24]
5/9 because you have to add those two together and put that number over the total number of marbles.
4 0
3 years ago
When e = 4, f = 2, and g = 8. If e varies jointly with f and g, what is the constant of variation?
jarptica [38.1K]
E\alpha fg
e=mfg
Where m is a constant of proportionality;
e=4, f=2 and g=8
Then;
4=m*2*8
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8 0
3 years ago
Write an augmented matrix of each system. Then, solve each system using matrix notation. Describe the solution set in vector not
Naddik [55]

Answer:

The answer is below

Step-by-step explanation:

Given the system of equations:

x + y + 2z = 9

2x + 4y - 3z = 1

3x + 6y - 5z = 0

This system of equation can be solved using matrix. This done by first representing the equations as matrix and then solving:

The matrix form is:

\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right]  \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right]  ^{-1} \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2&-17&11\\-1&11&-7\\0&3&-2\end{array}\right]   \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}1\\2\\3\end{array}\right]

5 0
3 years ago
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