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3 years ago

I need to know how to solve this completely not just the answers plz :)

Mathematics

1 answer:

svlad2 [7]3 years ago

5 0

I’m going to be honest, with these, I just straight plug the point into the solution abd which ever solution is true is the answer

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The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago

The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3

viva [34]

Answer:

$M_x$ = 8

$M_y$ = 6

Therefore the co-ordinate of the center of mass is = $(\frac{4}{5},\frac{3}{5})$

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

$M_x$ = ∑(mass × x-co-ordinate)

$M_y$ = ∑(mass × y-co-ordinate)

Therefore

$M_x$ = (4×2)+{3×(-3)}+(3×3)

$M_y$ = {4×(-3)}+{3×1}+(3×5)

The x co-ordinate of the center of mass is the ratio of $M_x$ to the total mass.

The y co-ordinate of the center of mass is the ratio of $M_y$ to the total mass.

Total mass (m) = m₁+ m₂+ m₃

= 4+3+3

=10

The x co-ordinate of the center of mass is $\frac {8}{10} = \frac {4}{5}$

The y co-ordinate of the center of mass is $\frac{6}{10}=\frac{3}{5}$

Therefore the co-ordinate of the center of mass is = $(\frac{4}{5},\frac{3}{5})$

4 0

3 years ago

How do you answer this ?

telo118 [61]

6 x 10 =60
40 x 24=960
maybe
I REALLY DON'T KNOW

8 0

3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

erma4kov [3.2K]

Answer:

a) $n = 9604$

b) n = 381

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?

When we do not know the proportion, we use $\pi = 0.5$ , which is when we are going to need the largest sample size.

The sample size is n when M = 0.01.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.01\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.01}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.01})^{2}$

$n = 9604$

b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?

Now we have that $\pi = 0.99$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.96\sqrt{\frac{0.99*0.01}{n}}$

$0.01\sqrt{n} = 1.96*\sqrt{0.99*0.01}$

$\sqrt{n} = \frac{1.96*\sqrt{0.99*0.01}}{0.01}$

$(\sqrt{n})^{2} = (\frac{1.96*\sqrt{0.99*0.01}}{0.01})^{2}$

$n = 380.3$

Rouding up

n = 381

7 0

3 years ago

A line, Z, has equation y = 5x + 3.<br> Write down an equation of a line parallel to line Z.

leva [86]

$\huge\underline\color{purple}{Answer \: ☘}$

$y = 5x$

Step-by-step explanation:

$as \: the \: line \: is \: parallel \: to \: line \: z \\ hence , \\ set \: the \: equation \: of \: the \: line \: as \\ y = kx + b \\ \\given... \\ y = 5x + 3 \\ comparing \: the \: equations \: we \: get \: \\ k = 5 \\ \\ hence \: the \: equation \: can \: be \: y = 5x$

hope helpful~

7 0

2 years ago

Read 2 more answers