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Lelu [443]
3 years ago
12

What is the length of DE ?? Thx :)

Mathematics
1 answer:
Sonbull [250]3 years ago
3 0

Answer:

A; 10

Step-by-step explanation:

What we can see here is that the triangles are similar.

Hence, the ratio of their sides are equivalent.

Thus, mathematically;

ED/BA = DF/AC = BC/EF

what we want to calculate is ED = x

Thus;

x/15 = 12/18

Cross multiply;

18 * x = 12 * 15

18x = 180

x = 180/18

x = 10

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A bag of marbles contains 5 red, 3 blue, 2 green, and 2 yellow marbles.
jeka57 [31]

Answer:

Step-by-step explanation:

P=5/12×2/12=5/72

7 0
3 years ago
Read 2 more answers
Does anyone know this? If you do can you please help me?
gladu [14]

Answer:

  • -2x > 30
  • x < -15

Step-by-step explanation:

A product is formed by multiplying the factors. Here, you want the product of -2 and x, so that is indicated as ...

  -2x

You want that product greater than 30. The symbol for "greater than" is >, so you have ...

  -2x > 30 . . . . the desired inequality

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The most straightforward way to solve this is to divide by the coefficient of x. Because that is negative, you must reverse the inequality symbol from "greater than" to "less than."

  x < 30/(-2)

  x < -15 . . . . . . the desired solution

_____

<em>Additional comment</em>

It may not be clear why multiplying or dividing an inequality causes the symbol to be reversed. You can think of it as reflecting the inequality over the point x=0 on the number line. Where larger numbers were on the right, they get reflected to points farther left, so as negative numbers, they are smaller numbers.

Consider ...

  1 < 2

  -1 > -2

5 0
3 years ago
How do you solve this
djyliett [7]
7 is the coefficient :)
6 0
3 years ago
What is 12 - 33/4 equal in fraction form?
Nadya [2.5K]

Answer:

3. 3/4

hope this helps

8 0
3 years ago
Use the definition of a Taylor series to find the first four nonzero terms of the series for f(x) centered at the given value of
kolbaska11 [484]

If <em>f(x)</em> = 7/(1<em> </em>+ <em>x</em>), then

<em>f</em> (2) = 7/3

<em>f '(x)</em> = -7/(<em>x</em> + 1)²   ==>   <em>f '</em> (2) = -7/9

<em>f ''(x)</em> = 14/(<em>x</em> + 1)³   ==>   <em>f ''</em> (2) = 14/27

<em>f '''(x)</em> = -42/(<em>x</em> + 1)⁴   ==>   <em>f '''</em> (2) = -14/27

Then the Taylor series of <em>f(x)</em> about <em>a</em> = 2 is

7/3 + 1/1! (-7/9) (<em>x</em> - 2) + 1/2! (14/27) (<em>x</em> - 2)² + 1/3! (-14/27) (<em>x</em> - 2)³

= 7/3 - 7/9 (<em>x</em> - 2) + 7/27 (<em>x</em> - 2)² - 7/81 (<em>x</em> - 2)³

5 0
3 years ago
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