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pshichka [43]
3 years ago
7

A package of cheese weighs 10 ounces. 200 grams is approximately 7 ounces.

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:

IT IS 285.7

Step-by-step explanation:

Kruka [31]3 years ago
3 0

Answer:

285.7 grams

Step-by-step explanation:

You will do this:

200/7 =28.57

28.57*10=285.71

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Note the slope intercept form: y = mx + b, in which m = slope

Isolate the y. Note the equal sign, what you do to one side, you do to the other. First, add 3x to both sides

-3x (+3x) + 6y = (+3x) + 12

6y = 3x + 12

Fully isolate the y. Divide 6 from both sides (and to all terms)

(6y)/6 = (3x + 12)/6

y = (3x)/6 + (12)/6

Simplify

y = (1/2)x + 2

y = 0.5x + 2 is your equation.

The slope is direclty left of the x (or the m variable). In this case, it is 0.5

0.5 is your answer (or 1/2 if wanted in fraction form)

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The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is soli
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(0,2)(-2,0)
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2 = 1(0) + b
2 = b
equation is : y = x + 2......solid line, means there is an equal sign....shaded below the line means less then....
ur inequality for this line is : y < = x + 2

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so ur inequality of this line is : y < -2x + 6

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\begin{tabular}&#10;{|c|c|c|c|c|c|}&#10; &Frequently&Occassionally&Not at all&Total\\[1ex]&#10;Male&227&454&798&1,479\\&#10;Female &205&450&747&1,402\\&#10;Total&432&904&1,545&2,881&#10;\end{tabular}

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}



Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

P(being&#10; \ female \ or \ not \ being \ involved)\\ \\= &#10;\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = &#10;\frac{2200}{2881}=\bold{0.764}



Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

P(being&#10; \ male \ or \ being \ frequently \ involved)\\ \\= &#10;\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = &#10;\frac{1684}{2881}=\bold{0.585}



Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

P(being&#10; \ female \ or \ not \ being \ frequently \ involved)\\ \\= &#10;\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = &#10;\frac{2654}{2881}=\bold{0.921}



Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
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