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lesantik [10]
3 years ago
14

Identify a counter example for the following conditional:

Mathematics
1 answer:
ira [324]3 years ago
5 0
The answer is C. Jonah Lincoln lives in Springfield, Illinois


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Helppppp please hdhdhd
JulijaS [17]

Answer:

C. The volume of the box is 625 cubic inches

Step-by-step explanation:

So if you take the 125 identical math cubes and multiply it by 5 which represents 5 cubic inches, you should get an answer of 625 cubic inches.

I hope this helped you!!! Enjoy the rest of your day :D

7 0
3 years ago
Read 2 more answers
Divide 9x^2 by 18y^2
Neporo4naja [7]

Step-by-step explanation:

√9x2√18y2. √9=3. √x2=x. √18=√9×2=3√2. √y2=y. Therefore √9x2√18y2=3x3√2y = x√2y.

3 0
2 years ago
Read 2 more answers
What is the solution to the system of equations. 2x+4y=12. Y=1/4x-3
larisa86 [58]
2/7 not sure but that's what i got 
5 0
3 years ago
A discount store takes 50% off of the retail price of a desk. For the store's holiday sale, it takes an additional 20% off of al
Serhud [2]

We are given the retail price of desk as $320. The store takes 50% off of the retail price of desk, then its price would become half of the original.

So its new price would be $160.

Now it says that it takes an additional 20% off of all furniture on store's holiday sale. So we need to cut off 20% from new price $160.

Holiday discount = 20% of $160 = 0.2 × 160 = 32.

Final selling price would be = $160 - $32 = $128.

So $128 is the final answer.

3 0
3 years ago
Read 2 more answers
Find an equation for those points P such that the distance from P to A(0, 1, 2) is equal to the distance from P to B(6, 4, 2). W
suter [353]

Answer:  The required equation for points P is 4x+2y=17.

Step-by-step explanation: We are give two points A(0, 1, 2) and B(6, 4, 2).

To find the equation for points P such that the distance of P from both A and B are equal.

We know that the distance between two points R(a, b, c) and S(d, e, f) is given by

RS=\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}.

Let the point P be represented by (x, y, z).

According to the given information, we have

PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.

Thus, the required equation for points P is 4x+2y=17.

8 0
3 years ago
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