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3 years ago

An anaerobic reaction takes place

1 answer:

6 0

As the name implies, anaerobic means there is no presence of oxygen. So if it will take place, it will only take place in little or no oxygen which is in the last sentence in the following choices. First and second choice are wrong for there is a need of oxygen required when there is no oxygen is needed and the presence of nitrogen in water.

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2A1 (s) + 3C12 (g) --> 2AlCl3 (s) (balanced)

Dennis_Churaev [7]

Answer:

32.3%

Explanation:

Percent yield is defined as:

Actual yield (125.5g) / Theoretical Yield * 100

To find theoretical yield we have to find the moles of aluminium. As 2 moles of Al produce 2 moles of AlCl3, the moles of Al = Moles AlCl3.

With these moles we can find the mass assuming a 100% of yield (Theoretical Yield) as follows:

<em>Moles Al = Moles AlCl3 (Molar mass Al = 26.98g/mol)</em>

72g Al * (1mol / 26.98g) = 2.67 moles AlCl3

<em>Mass AlCl3 (Molar mass: 133.34g/mol)</em>

2.67 moles AlCl3 * (133.34g / mol) = 355.8g AlCl3

Percent Yield = 125.5g / 355.8g * 100 =

5 0

3 years ago

A student mixed a small amount of iron filings and sulphur powder in a dish. He could not

Temka [501]

Answer:

$\huge \boxed{\mathrm{Carbon \ disulphide}}$

Explanation:

Carbon disulphide is the liquid that can be used to separate iron fillings and sulphur powder.

When carbon disulphide is poured into the dish, the sulphur powder gets easily dissolved in the carbon disulfide. The iron fillings are left to settle on the bottom of the dish.

The iron fillings can get seperated through filtration. When the mixture of sulphur powder and carbon disulphide gets completely evaporated, the sulphur powder is left over.

7 0

3 years ago

A titration reaction requires 38.20 mL phosphoric acid solution to react with 71.00 mL of 0.348 mol/L calcium hydroxide to reach

NARA [144]

1a. The balanced equation for the reaction is:

1b. The number of mole of Ca(OH)₂ is 0.0247 mole

1c. The number of mole of H₃PO₄ is 0.0165 mole.

1d. The concentration of H₃PO₄ is 0.432 mol/L

2. The new concentration of the H₃PO₄ solution is 0.0432 mol/L

<h3>1a. The balanced equation for the reaction</h3>

<u>3</u>Ca(OH)₂ + <u>2</u>H₃PO₄ —> Ca₃(PO₄)₂ + <u>6</u>H₂O

<h3>1b. Determination of the mole of Ca(OH)₂</h3>

Volume of Ca(OH)₂ = 71 mL = 71 / 1000 = 0.071 L

Concentration of Ca(OH)₂ = 0.348 mol/L

Mole = Concentration × Volume

Mole = 0.348 × 0.071

<h3>1c. Determination of the mole of H₃PO₄. </h3>

3Ca(OH)₂ + 2H₃PO₄ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

3 moles of Ca(OH)₂ reacted with 2 moles of H₃PO₄.

Therefore,

0.0247 moles of Ca(OH)₂ will react with = $\frac{0.0247 * 2}{3}$ = 0.0165 mole of H₃PO₄.

Thus, the number of mole of H₃PO₄ is 0.0165 mole

<h3>1d. Determination of the concentration of H₃PO₄</h3>

Volume of H₃PO₄ = 38.20 mL = 38.20/ 1000 = 0.0382 L

Mole of H₃PO₄ = 0.0165 mole

<h3>Concentration of H₃PO₄ =?</h3>

$Concentration = \frac{mole}{volume} \\\\Concentration = \frac{0.0165}{0.0382}$

<h3>Concentration of H₃PO₄ = 0.432 mol/L</h3>

<h3>2. Determination of the new concentration of the H₃PO₄ solution.</h3>

Initial Volume (V₁) = 10 mL

Initial concentration (C₁) = 0.432 mol/L

New volume (V₂) = 100 mL

<h3>New concentration (C₂) =?</h3>

The new concentration of the H₃PO₄ solution can be obtained as follow:

0.432 × 10 = C₂ × 100

4.32 = C₂ × 100

Divide both side by 100

C₂ = $\frac{4.32}{100}\\$

Therefore, the new concentration of the H₃PO₄ solution is 0.0432 mol/L

Learn more:

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3 0

3 years ago

Mass = 35g Volume = 7cm3 What is the Density?

olga_2 [115]

Answer:

5 g/cm^3

Explanation:√3V=1.91293cm

7 0

3 years ago

A chemist adds of a zinc nitrate solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has a

Ray Of Light [21]

Answer:

5.3 × 10⁻³ kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution. The moles of zinc nitrate are:

0.1350 L × 0.21 mol/L = 2.8 × 10⁻² mol

The molar mass of zinc nitrate is 189.36 g/mol. The mass corresponding to 2.8 × 10⁻² moles is:

2.8 × 10⁻² mol × 189.36 g/mol = 5.3 g

1 kilogram is equal to 1000 grams. Then,

5.3 g × (1 kg/1000 g) = 5.3 × 10⁻³ kg

8 0

3 years ago