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3 years ago

PLEASE HELP I WILL GIVE BRAINLEST

1 answer:

4 0

The theoretical probability of getting heads or tails is 1/2 the time.

1/2 of 150 = 75

So theoretically you would get 75 heads and 75 tails.

The experiment got 84 heads, which is greater than 75, so it would be higher than the theoretical probability.

The answer is : <span>It is 6% higher than the theoretical probability.</span>

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Which quantity could go in the blank to make the equation true?

denpristay [2]

3x because 3x+2x=5x hope this helps

4 0

3 years ago

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Solve the equation using square roots. Write your answer in simplest form.<br> Question in picture

GalinKa [24]

Answer:

The solutions to the quadratic equation involving square roots are:

$x=2\sqrt{7}i+8,\:x=-2\sqrt{7}i+8$

Step-by-step explanation:

Given the equation

$\frac{1}{4}\left(x-8\right)^2+8=1$

subtract 8 from both sides

$\frac{1}{4}\left(x-8\right)^2+8-8=1-8$

$\frac{1}{4}\left(x-8\right)^2=-7$

$\left(x-8\right)^2=-28$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

solving

$x-8=\sqrt{-28}$

$x-8=\sqrt{-1}\sqrt{28}$

$x-8=\sqrt{28}i$ ∵ $\sqrt{-1}=i$

$x=2\sqrt{7}i+8$

similarly solving

$x-8=-\sqrt{-28}$

$x-8=-2\sqrt{7}i$

$x=-2\sqrt{7}i+8$

Therefore, the solutions to the quadratic equation involving square roots are:

$x=2\sqrt{7}i+8,\:x=-2\sqrt{7}i+8$

5 0

3 years ago

In the diagram, AD=CD=CB and measure of angle A=40°. How many degrees are in angle DCB?

Ad libitum [116K]

Answer:

$20^{\circ}$

Step-by-step explanation:

Consider triangle ACD. This triangle is isosceles triangle, because AD = DC. Angles adjacent to the base AC are congruent abgles, so

$m\angle DAC=m\angle DCA=40^{\circ}$

The sum of the measures of all interiror angles in the triangle is always $180^{\circ},$ then

$m\angle DAC+m\angle DCA+m\angle ADC=180^{\circ}\\ \\40^{\circ}+40^{\circ}+m\angle ADC=180^{\circ}\\ \\m\angle ADC=180^{\circ}-40^{\circ}-40^{\circ}=100^{\circ}$

Angles ADC and BDC are supplementary angles (add up to $180^{\circ}$ ), then

$m\angle BDC=180^{\circ}-100^{\circ}=80^{\circ}$

Consider triangle BCD. This triangle is isosceles triangle because BC = DC. Angles adjacent to the base BD are congruent abgles, so

$m\angle BDC=m\angle DBC=80^{\circ}$

The sum of the measures of all interiror angles in the triangle is always $180^{\circ},$ then

$m\angle DBC+m\angle BDC+m\angle BCD=180^{\circ}\\ \\80^{\circ}+80^{\circ}+m\angle BCD=180^{\circ}\\ \\m\angle BCD=180^{\circ}-80^{\circ}-80^{\circ}=20^{\circ}$

6 0

3 years ago

Free_Kalibri [48]

Answer:

d. Yes, there appears to be a linear trend, but the fit is not exact.

Step-by-step explanation:

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3 years ago

alias's hair grows at a rate of about 1/2 inch per month. how many months will it take her hair to grow 8 inches?

Vlad [161]

Answer:

16 months to grow hair to 8 inches

3 0

4 years ago

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