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mars1129 [50]
3 years ago
12

Me groves has trays of paint for her students. Each tray has 5 colors. One of the colors is purple. What fraction of the colors

in 20 trays is purple
Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0
Purple = 1/5 of the colors

5 colors per tray, 20 trays = 5 * 20 = 100 colors

1/5 * 100 = 100/5 = 20

20 colors are purple

20/100 = 1/5

1/5
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Please answer now plz!!!! A farmer is trying to determine the number of plaintiff plaints in a farm that covers 21 acres. He mar
Natali5045456 [20]

Answer:

D) 12,656

Step-by-step explanation:

First of all, as they have given us 3 quantities of plants in 1/2 an acre, we can work out the average amount of plants in 1 whole acre.

In the first 1/2 acre there were:

  • 291 plants

In the second 1/2 acre there were:

  • 327 plants

In the third 1/2 acre there were:

  • 286 plants

to work out the average, we add all these together then divide them by 3 (as there are 3 examples)

291 + 327 + 286 = 904

904 ÷ 3 = 301.3 (this is the average amount of plants in every 1/2 acre.) If we multiply this answer by 2 we will get the average amount of plants in every acre.

301.3 x 2 = 602.67 (average plants in every 1 acre) multiply by total acres (21) for your answer

602.67 x 21 = 12656 average plants in total

I hope this was helpful :-)

8 0
3 years ago
What is the initial number of views?<br><br>A.0<br>B.100<br>C.110<br>D.11​
Nataly_w [17]

Answer:

A

Step-by-step explanation:

O because that is the number that you always start off.

3 0
2 years ago
Read 2 more answers
Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?
taurus [48]

Step-by-step explanation:

As we know that f is a polynomial function, the values of x for which f(x)=0 are said to be the zeros of  f.

Factoring the polynomial equation, if it is eligible to get factored, setting each factor equal to zero and solving can determine the zeros.

So, it is clear from above that option A i.e.  h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right) and option C i.e. h\left(x\right)\:=\:4\left(x^2\:-\:4\right) displays the zeros of function h, as they can be factored by setting each factor equal to zero.

Option A)

Lets solve them to get the zeros of these functions.

Considering the function

h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right)

\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)

-4\left(x-2\right)\left(x+2\right)=0

Using the Zero Factor Principle:

\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

\mathrm{Solve\:}\:x-2=0:\quad x=2

\mathrm{Solve\:}\:x+2=0:\quad x=-2

\mathrm{The\:zeros\:to\:the\:quadratic\:equation\:are:}

x=2,\:x=-2

Option B)

Considering the function

h\left(x\right)\:=\:4\left(x^2\:-\:4\right)

\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)

4\left(x^2-4\right)=0

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4\left(x^2-4\right)}{4}=\frac{0}{4}

x^2-4=0

x^2=4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

Although the zeros of the function h\left(x\right)=-4x^2\:+\:16 can also be obtained for the function by similar method. But, for this we would have to solve them before determining the zeros.

For example,

Considering the function

h\left(x\right)=-4x^2\:+\:16

\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)

-4x^2+16=0

-4x^2+16-16=0-16

-4x^2=-16

x^2=4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

Keywords: zeros, quadratic function

Learn more about zeros, quadratic function from brainly.com/question/12531669

#learnwithBrainly

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3 years ago
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Option b) definitely i think
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8x^3y+x^2-14z-2+5y^2x in standard form
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11x^8y^2-14z-2 I believe
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