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damaskus [11]
3 years ago
11

3 and 1/4 times -2 and 3/5? Answers: A. -8 9/20 B. -6  and 3/20 C. 6 and 3/20 D. 8 and 9/20

Mathematics
2 answers:
sashaice [31]3 years ago
6 0
3\frac{1}{4}*(-2\frac{3}{5})= \frac{13}{4}*(-\frac{13}{5})=-\frac{13*13}{4*5}=-\frac{169}{20}=-8\frac{9}{20}
wolverine [178]3 years ago
6 0
3\frac{3}{4}\cdot(-2\frac{3}{5})=\frac{3\cdot4+1}{4}\cdot\left(-\frac{2\cdot5+3}{5}\right)=\frac{13}{4}\cdot\left(-\frac{13}{5}\right)=-\frac{13\cdot13}{4\cdot5}=-\frac{169}{20}=-8\frac{9}{20}\\\\\\Answer:A
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A monument in the shape of a right triangle sits on a rectangular pedestarl that is 7 meters high by 16 meters long. The longest
SashulF [63]

Answer:

height = 63  m

Step-by-step explanation:

The shape of the monument is a triangle. The triangle is a right angle triangle. The triangular monument is sitting on a rectangular pedestal that is 7 m high and 16 m long.  The longest side of the triangular monument is 65 m . The longest side of a right angle triangle is usually the hypotenuse. The adjacent side of the triangle which is the base of the triangle sitting on the rectangular pedestal is 16 m long.

Since the triangle  formed is a right angle triangle, the height of the triangular monument can be gotten using Pythagoras's theorem.

c² = a² + b²

where

c is the hypotenuse side while side a and b is the other sides of the right angle triangle.

65² - 16² = height²

height² = 4225  - 256

height² = 3969

square root both sides

height = √3969

height = 63  m

4 0
3 years ago
joshua drinks 8 cups of water a day. The recommended daily amout is given in fluid ounces.How many fluid ounces of water does he
olga nikolaevna [1]
1 cup = 8 fluid oz

8 × 8 = 64 

So Joshua drinks 64 fluid ounces a day

Hope this helped. Have a great day!
5 0
3 years ago
Read 2 more answers
Find m <br> A. 40°<br> B. 80°<br> C. 130°<br> D. 260°
alekssr [168]
The answer to this is A. 40
3 0
3 years ago
Read 2 more answers
Describe at least two similarities between constructing a perpendicular line through a point on a line and constructing a perpen
Sophie [7]

Two similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line are;

  • 1. Arcs are drawn to cross the given line twice on either side relative to the point
  • 2. The perpendicular line is drawn using a straight edge by connecting the small arcs formed using the arcs from step 1, to the point on the line or off the line

Description:

1. One of the first steps is to place the compass on the point and from

point, draw arcs to intersect or cross the given line at two points.

2. The compass is placed at each of the intersection point in step 1 and

(opened a little wider when constructing from a point on the line) arcs are

drawn on one (the other side of the point off the line) side of the line with

the same opening (radius) of the compass to intersect each other.

3. From the point of intersection of the arcs in step 2, a line is drawn with a

straight edge passing through the given point.

Learn more about perpendicular lines here:

brainly.com/question/11505244

8 0
2 years ago
If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b
Readme [11.4K]

Answer:

  • Exact distance = 90\sqrt{2} feet
  • Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0
2 years ago
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