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Vesna [10]
3 years ago
8

See attachment to help.

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0
B.
because {1,1,3,5,8}
{2,2,4,6,9}

you're just counting the numbers after the one that was given to you.
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Which are the solutions of x2 = -5x + 8?
Oksana_A [137]

Answer:

1.27, -6.27 to the nearest hundredth,

or if you require it in exact form,

-2.5 + √14.25,   -2.5 - √14.25.

Step-by-step explanation:

x^2 = -5x + 8

x^2 + 5x  = 8

Competing the square:

(x + 2.5)^2 - 6.25 = 8

(x + 2.5) = 14.25

x + 2.5 = +/-√14.25

x = -2.5 + √14.25,   -2.5 - √14.25

x = -2.5 + 3.77,  -2.5 - 3.77

= 1.27, -6.27.

6 0
3 years ago
Which pair of expressions are equivalent?
Zielflug [23.3K]

Answer:

second one

Step-by-step explanation:

Because when you try to remove the brackets then you should multiply coefficient of x and coefficient of y by 2

So it will be 2x+18y

2*9=18

4 0
3 years ago
One counting number is 4 times great as a counting number.The product of the two number is 36.What is the sum of the two number
VARVARA [1.3K]

Answer:

The sum of the two numbers is 15

Step-by-step explanation:

Let the counting numbers be x and y.

Then we can write the following equations

x=4y.......1 (one is four times greater )

x(y)=36.....2 (the product of the two)

Putting equation 1 into equation 2, we get

4y(y)=36

{4y}^{2} = 36

Dividing through by 4,we get

{y}^{2} =  \frac{36}{4}

{y}^{2} = 9

Taking square root of both side, we obtain

y=3

Putting the value of y into equation , we get

x=4(3)=12

Hence the numbers are 3 and 12

Therefore the sum of the two numbers is 3+12=15

3 0
3 years ago
A recipe calls for 5 8 pound of cheese per batch. Assuming you have enough of the other ingredients, how many batches of the rec
aliya0001 [1]
I assume you mean 5/8 of a pound not 58 pounds. In that case convert your total number of pounds into eights to make it easier to calculate. 5 pounds is equal to 40/8 pounds of cheese. Now divide this by 5/8. That equals 8. SO you can make 8 batches.
3 0
3 years ago
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0
3 years ago
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