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san4es73 [151]
3 years ago
8

On every 3rd day Ivan goes to the gym to exercise. Every 5th day Gavin goes to the gym to exercise. What is the first day Ivan a

nd Gavin will be at the gym on the same day.
Mathematics
2 answers:
Colt1911 [192]3 years ago
8 0
You have to find the LCM (least common multiple) of both numbers.

3: 3, 6, 9, 12, 15
5: 5, 10, 15

ivan and gavin will be together at the gym on the 15th day.
Feliz [49]3 years ago
8 0
The fifteenth day is the first day they'll cross paths because 15 is the lowest common multiple for 3 and 15 also 3x5=15

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Y = 5<span><span>(x+<span>32</span>)^</span>2 </span>− <span><span>53/4 (the / is for fraction)</span></span>
4 0
4 years ago
The ordered pair(5,-3) is a solution to which of the following inequalities?
Dmitrij [34]

A plumber worked 26 hours a week for half a year. If his hourly wage was $40, how much did he earn during this time period?

<span> <span>A.</span>$1040</span><span> <span>B.</span>$27,040</span><span> <span>C.</span>$54,080</span><span> <span>D.</span><span>$520</span></span>
7 0
3 years ago
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
Construct an augmented matrix for this linear system: x − y − 4z = 5 2x 2z = 0 4x y z = 3.
Crazy boy [7]

The augmented matrix is,

\left(\begin{array}{ccccc}1&-1&-4&|&5\\2&0&2&|&0\\4&1&1&|&3\end{array}\right)

We have given system of linear equation is,

x - y - 4z = 5,2x + 2z = 0 ,4x +y +z = 3.

<h3>What is the meaning of augmented matrix?</h3>

In an augmented matrix, each row represents one equation in the system and each column represents coefficients (with signs) of variables or the constant terms.

So, the first row is

1\ -1\ -4\ 5

the second row is

2\ 0\ 2\ 0

and the third row is

4\ 1\ 1\ 3

Therefore the augmented matrix for this linear system is,

\left(\begin{array}{ccccc}1&-1&-4&|&5\\2&0&2&|&0\\4&1&1&|&3\end{array}\right)

To learn more about the augmented matrix visit:

brainly.com/question/14600951

7 0
2 years ago
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Solve:
STatiana [176]

The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

The given equation is:

3-k=\sqrt{3k+1}

Square both sides of the equation

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Expand the left side of the equation above

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Write the quadratic equation in standard form

k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\

Factor the quadratic equation

(k-8)(k-1)=0

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

Learn more here: brainly.com/question/25840704

8 0
3 years ago
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