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san4es73 [151]
3 years ago
8

On every 3rd day Ivan goes to the gym to exercise. Every 5th day Gavin goes to the gym to exercise. What is the first day Ivan a

nd Gavin will be at the gym on the same day.
Mathematics
2 answers:
Colt1911 [192]3 years ago
8 0
You have to find the LCM (least common multiple) of both numbers.

3: 3, 6, 9, 12, 15
5: 5, 10, 15

ivan and gavin will be together at the gym on the 15th day.
Feliz [49]3 years ago
8 0
The fifteenth day is the first day they'll cross paths because 15 is the lowest common multiple for 3 and 15 also 3x5=15

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March is 8 months away from August and the target amount is $600.
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December=$86.4 + (0.2*$86.4)=$103.68
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Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4t
Umnica [9.8K]

Answer:

<h3>The option A) x^{10}z^7 is correct answer.</h3><h3>The correct simplification for the given expression \frac{x^{12}\times z^{11}}{x^2\times z^4} is x^{10}z^7</h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as \frac{x^{12}\times z^{11}}{x^2\times z^4}

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

\frac{x^{12}\times z^{11}}{x^2\times z^4}

=x^{12}\times z^{11}(x^{-2}\times z^{-4})   ( by using the identity \frac{1}{a^m}=a^{-m} )

=(x^{12}.x^{-2})\times (z^{11}.z^{-4})

=x^{12-2}\times z^{11-4} ( by using the identity a^m.a^n=a^{m+n} )

=x^{10}\times z^7

=x^{10}z^7

∴ \frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7

<h3>The correct simplification for the given expression \frac{x^{12}\times z^{11}}{x^2\times z^4} is x^{10}z^7</h3><h3>Hence option A) x^{10}z^7 is correct answer.</h3>

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