(a) If <em>f(x)</em> is to be a proper density function, then its integral over the given support must evaulate to 1:

For the integral, substitute <em>u</em> = <em>x</em> ² and d<em>u</em> = 2<em>x</em> d<em>x</em>. Then as <em>x</em> → 0, <em>u</em> → 0; as <em>x</em> → ∞, <em>u</em> → ∞:

which reduces to
<em>c</em> / 2 (0 + 1) = 1 → <em>c</em> = 2
(b) Find the probability P(1 < <em>X </em>< 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

Answer:5.86 9.26
Step-by-step explanation:
Answer:
$1016.4 - if this is just a simple multiplication question
Answer:
6p =120
Step-by-step explanation:
well the p's are very close together in a sense that we are going to multiply instead of add because they the p's would have space in between
6 * 20 = 120
so p= 20