Help plz plz plz i need help, not good at math
1 answer:
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Answer:
s = 14
Step-by-step explanation:
Step 1: Combine like terms.
Step 2: Multiply both sides by 2/3.
Answer:
B. A cow of 5 years is predicted to produce 5.5 more gallons per week.
Step-by-step explanation:
Let , where
is the age of the dairy cow, measured in years, and
is the predicted milk production, measured in gallons per week.
Besides, we consider and
, such that
, we define the difference between predicted milk productions (
) below:
(1)
If we know that and
, then the difference between predicted milk productions is:
That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.
We are given these three people age below:
- Jim's age
- Carla's age
- Tomy's age
We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.
- Jim's age = x
Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.
- Carla's age = x+5
Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).
- Tomy's age = 6+(x+5)
The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.
Combine like terms and solve for x.
Then we substitute the value of x in ages to find these three people ages.
- Jim's age = x = 5
- Carla's age = x+5 = 5+5 = 10
- Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.
Answer
- Jim's age = 5
- Carla's age = 10
- Tomy's age = 16