1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anit [1.1K]
3 years ago
9

Analyzing data in graphs or charts allows you to?

Biology
1 answer:
sashaice [31]3 years ago
3 0
A. make observations.
You might be interested in
The four bases contained in dna are _____. the four bases contained in dna are _____. cytosine, guanine, thymine, uracil adenine
Bess [88]
The four bases in DNA are: adenine, thymine, cytosine, guanine.
In RNA, thymine gets replaced by uracil. 
Purine is only a name for the two bases guanine and adenine. 
7 0
3 years ago
Impaired and delayed healing in a person with diabetes is caused by chronic complications that include:
juin [17]
Chronic neuropathies
3 0
3 years ago
Please write the code of the transcribed RNA strand from this DNA:<br> ATTTOCATOCA
Snezhnost [94]
Im not sure cuz why theres O in there? I thought there’s only 4 bases Adenine Thymine Guanine Cytosine and in RNA there’s Uracil instead of Thymine. Sorry
6 0
3 years ago
Muscles are responsible for all expect of blood formation
Anit [1.1K]
This sentance is true
5 0
3 years ago
A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
6 0
3 years ago
Other questions:
  • Enzymes can be affected by acidity and alkalinity. What name is given to the scale that measures acidity and alkalinity?​
    15·1 answer
  • Which terms describe the stem and root of this plant?
    5·1 answer
  • How do you put allele in a sentence
    13·1 answer
  • Plant and animal cells are both eukaryotic, and thus they are similar in many ways. However, plant cells have some structures th
    7·1 answer
  • Which is the definition of an embryo?
    15·2 answers
  • One cat carries heterozygous, long-haired traits (Ss), and its mate carries homozygous short-haired traits (ss). Use a Punnett s
    13·1 answer
  • Which describe the effects of climate on the rate if weathering
    11·2 answers
  • What is the human female reproductive system is adapted for? A. Production of zygotes in ovaries B. External fertilization of ga
    9·1 answer
  • The north pole and the magnetic pole are what? a-located at the same point b-located near each other c-two different names for t
    8·1 answer
  • Which of the following is the definition of animal husbandry?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!