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Daniel [21]
3 years ago
5

-3/7 +2z <49 how to work this?

Mathematics
2 answers:
Ivan3 years ago
8 0

The answer would be z < 173 / 7 . I hope this helps.


Zepler [3.9K]3 years ago
3 0

We need to isolate z on one side of the equation.

First, add 3/7 to both sides of the equation (this will cancel out the -3/7):

2z < 49 + 3/7

Let's change (49+3/7) into an improper fraction:

2z < 346/7

Divide both sides by 2 to get the answer:

z < 173/7

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What is the nth term of quadratic sequence 4 7 12 19 28
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We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:

Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².

We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.

Now we find the difference between the actual terms of the sequence and the numbers we just found:

4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.

Since this is constant, the sequence is in the form (1/2a)n²+d;
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The correct answer is n²+3
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