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3 years ago

-q-7q=8 whats q equal?

1 answer:

7 0

-q-7q=8
First you need to know that there is an invisible 1 in front of -q. Change it to -q if you need to. You get:
-1q-7q=8
add like terms: -1-7 gives you -8.
-8q=8. Divide by -8 on both sides to find q.
-8/8=-1
8/8=1
Therefore, q=1.

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miv72 [106K]

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3 years ago

4. Harry is going to send some flowers to his wife. Summerfield Florist charges $1 per rose, plus

k0ka [10]

The number of roses purchased will be; 12 roses

The total cost of the bouquet is; $51

Let number of roses be x

For Summerfield florists;

At $1 per rose and $39 for the vase, cost is;

C = x + 39

For grayson's flowers;

At $3 per rose and $15 for the vase,total cost is;

C = 3x + 15

We are told when he orders a certain number of roses, the cost will be the same with each flower shop.

Thus;

x + 39 = 3x + 15

3x - x = 39 - 15

2x = 24

x = 24/2

x = 12

Total cost is;

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C = $51

Read more about cost functions at; brainly.com/question/19300938

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2 years ago

Which statement is not one of the five essential parts needed to construct a good proof? a. Develop a system of inductive reason

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3 years ago

The product of a number squared and three is equal to seven

gogolik [260]

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2 years ago

V= 512^2/3* 19683^1/3*256^1/4

irina1246 [14]

Answer:

V=512^2/3* 19683^1/3*256^1/4 = 6912

Step-by-step explanation:

V= $(512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times (256^{\frac{1}{4} } )\\$

$2^{9} = 512\\2^{8} = 256\\19683^{\frac{1}{3} } = 27\\$

putting values in equation

V= $2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } } \\$ let it be equation 1

$2^9^{\frac{2}{3} } = 2^6 according\,to\,exponential\,rule\\2^8^\frac{1}{4} = 2^2 according\,to\,exponential\,rule\\\\$

putting values in equation 1

$V= 2^6\times 27\times 2^2$

According to exponential rule $2^6 \times 2^2 = 2^8$

V= $2^8 \times 27\\$

$V=256\times 27\\V=6912$

V= 6912

Keywords: Algebra

Learn more about algebra at:

#learnwithBrainly

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3 years ago