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3 years ago

What is equivalent to the square root of -27

1 answer:

3 0

For the square root of a negative number, you would have to get into imaginary numbers. If you haven't learned about it yet, then the answer would be no real solutions. But if you have, here's how to solve it:

First, identify that 9 x 3 = 27. To after taking the square root, you will get 3√3 (Since the square root of 9 is 3 and there's no square root of 3, so leave it in the √)

However, since it is a negative number, you will have to include the letter i in the answer. i represents the imaginary part of it since you can't have a negative number in the square root.

So your answer will look like 3i√3.

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Mara's family is driving to her grandmothers' house. The family travels 239.4 miles between the hours of 9:10 a.M. To 1:40 p.M.

anzhelika [568]

Answer:

53.2 mph

Step-by-step explanation:

Mara's family travels 239.4 miles between the hours of 9:10 a.m. to 1:40 p.m.

1:40 p.m. is 13:40.

Thus, they traveled for

13 hours 40 minutes - 9 hours 10 minutes = 4 hours 30 minutes

that is $4\frac{1}{2}=4.5$ hours.

Use formula:

$D=r\cdot t,$

where

D = distance

r = rate

t = time.

In your case,

D = 239.4 miles

t = 4.5 hours

Hence,

$239.4=4.5r\\ \\r=\dfrac{239.4}{4.5}=53.2\ mph$

5 0

3 years ago

Read 2 more answers

Plsssss helps 50 points

lutik1710 [3]

Here's the solution,

volume of cylinder :

=》

$\pi r {}^{2} h$

where,

r = radius
h = height

now, let's solve

=》

$3.14 \times 7 \times 7 \times 13$

=》

$2000.18$

So, volume = 2000.2 cm³

3 0

3 years ago

Read 2 more answers

What is the difference between intermediate algebra and algebra 1?

Igoryamba

Algebra 1 just really teaches you the basics of algrebra

6 0

3 years ago

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(x+3)²(65)=x(6)<br>Solve using quadric formula

Angelina_Jolie [31]

Step 1: Simplify both sides of the equation.

65x²+390x+585=6x

Step 2: Subtract 6x from both sides.

65x²+390x+585−6x=6x−6x
65x²+384x+585=0

For this equation: a=65, b=384, c=585

65x²+384x+585=0

Step 3: Use quadratic formula with a=65, b=384, c=585

x=−b±√b2−4ac/2a
x=−(384)±√(384)2−4(65)(585)/
2(65)
x=−384±√−4644/130

Therefore, There are no real solutions.

6 0

2 years ago

Read 2 more answers

The perimeter of a semicircle is 5.14 feet. What is the semicircle’s area?

hammer [34]

$\bf \textit{circumference of a semi-circle}\\\\
C=\pi r\qquad 
\begin{cases}
r=radius\\
-----\\
C=5.14
\end{cases}\implies 5.14=\pi r\implies \boxed{\cfrac{5.14}{\pi }=r}\\\\
-------------------------------\\\\
\textit{area of a semi-circle}\\\\
A=\cfrac{\pi r^2}{2} \implies A=\cfrac{\pi }{2}r^2\implies A=\cfrac{\pi }{2}\left( \boxed{\cfrac{5.14}{\pi }} \right)^2
\\\\\\
A=\cfrac{\pi }{2}\implies \cfrac{5.14^2}{\pi ^2}\implies A=\cfrac{26.4196}{2\pi }\implies A=\cfrac{13.2098}{\pi }$

5 0

3 years ago