At 55 mph it will take you approximately _____ feet to stop the car. A. 5 feet B. 100 feet C. 228 feet
1 answer:
Answer:
The correct answer is option C, 228 feet
Step-by-step explanation:
As per Newton’s third law of motion:
V2 – U2 = 2 x a x S
Where V = final velocity
U = Initial Vlocity
a = acceleration (-ve)
S= distance travelled
V= 0 mph
U= 55 mph = 80.6667 ft /sec
0 – (80.6667 ft /sec)2 = 2 x (-g/2) x S
S = (80.6667 ft /sec)2 /(32.2 feet per second per second x0.5)
S = 202.1 feet
So the most nearest option is option C
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