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2 years ago

At 55 mph it will take you approximately _____ feet to stop the car. A. 5 feet B. 100 feet C. 228 feet

Mathematics

1 answer:

ololo11 [35]2 years ago

6 0

Answer:

The correct answer is option C, 228 feet

Step-by-step explanation:

As per Newton’s third law of motion:

V2 – U2 = 2 x a x S

Where V = final velocity

U = Initial Vlocity

a = acceleration (-ve)

S= distance travelled

V= 0 mph

U= 55 mph = 80.6667 ft /sec

0 – (80.6667 ft /sec)2 = 2 x (-g/2) x S

S = (80.6667 ft /sec)2 /(32.2 feet per second per second x0.5)

S = 202.1 feet

So the most nearest option is option C

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Convert 38degrees F to degrees celsius. If necessary, round your answer to the nearest tenth of a degree. Here are the formulas.

vekshin1

$F=38 \\ \\C= \frac{5}{9} (F-32)=\frac{5}{9} (38-32)=\frac{5}{9}\times6= \frac{30}{9} \approx 3.33$

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3 years ago

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A line goes through the point (-3,2) and has a slope of 1. Write the equation of this line in standard form .

asambeis [7]

Answer:

y - 2 = x + 3

y = x + 5

-x + y = 5 standard form

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3 years ago

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jenyasd209 [6]

The expression that represents the number of days until only 10% remains is

T((d) 10%) = 100 • (1/2)^3.322

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3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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2 years ago

Find the distance between two points (5,10) and (-4,6)

Helga [31]

Answer:

Explanation:

The formula for calculating the distance between two points is:

√

(

−

)

(

−

)

Substituting the values from the points in the problem gives:

√

(

−

)

(

−

)

√

(

−

)

(

−

)

d = √ ( − 3 ) 2+ 1 2

d = √ 9+ 1

d = √ 10

d = 3.162

rounded to the nearest thousandth

7 0

2 years ago