Given nth term of an AP = 7-4n
Put n = 1 then t1 = 7-4(1) = 7-4 = 3
Put n = 2 then t2 =7-4(2) = 7-8 = -1
Common difference = t2-t1 = -1-3 = -4
Answer:
Range is 3 <= g(x) <= 27.
Step-by-step explanation:
The range is the values of g(x) for the given domain.
When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.
When x = 4 g(x) = 3(4)^2 - 6(4) + 3 = 27.
Answer:
Looks right, b is right
Step-by-step explanation:
The rest are false
Answer:
x = - 10
Step-by-step explanation:
Express the fractions on the left side as a single fraction.
Multiply the numerator/denominator of the first fraction by (x - 2)
Multiply the numerator/denominator of the second fraction by (x + 1)
+ = 3
Distribute the numerators and simplify
= 3 ( cross- multiply )
3x² - 2x + 4 = 3(x+ 1)(x - 2) ← distribute
3x² - 2x + 4 = 3(x² - x - 2)
3x² - 2x + 4 = 3x² - 3x - 6 ( subtract 3x² - 3x from both sides )
x + 4 = - 6 ( subtract 4 from both sides )
x = - 10