A line is perpendicular to y = {2/3x + 2/3}
1 answer:
Answer: y = (-3x/2) + 1
Step-by-step explanation:
From the standard equation y = mx + c, the slope of the equation is 2/3. Therefor slope of a line perpendicular to it will be -3/2.
Hence the equation will be
y = (-3x/2) + c
As this line passes through (-2,4), putting these values in this equation gives c = 1.
Hence the answer is y = (-3x/2) + 1
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-5×2(xe^x^2)y-5e^x^2dy/dx=1
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