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3 years ago

Who is good at the maths/ algebra??

Mathematics

1 answer:

Goryan [66]3 years ago

3 0

8 < 2b
8/2 < b
4 < b

2b + 15 < 5
2b < 5 - 15
2b < -10
b < -10/2
b < -5

answer is : b > 4 or b < -5

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An airplane flew a distance of 650 km at an average speed of 300 km/h. How much time did the flight take

galina1969 [7]

650/300 = 2(1/6)
(1/6) of 1 hour = 10mins
The flight took 2hr and 10mins.

6 0

3 years ago

Please help my friend. She needs to get 1000 subs by next month.

noname [10]

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8 0

3 years ago

Read 2 more answers

A and B are two similar shapes the area of shape A is 200cm2 calculate the area of shape B

barxatty [35]

Answer:

Area of shape B = 312.5 cm²

Step-by-step explanation:

Ratio of Area of A : Area of B = 12² : 15²

Given that area of A is 200 cm², let the area of shape B = x

Therefore:

200:x = 12²:15²

200/x = 144/225

Cross multiply

144x = 200*225

144x = 45,000

x = 45,000/144

x = 312.5 cm²

Area of shape B = 312.5 cm²

5 0

3 years ago

How do you graph a circle x^2 + y^2=25 and the line is given y=2

Kazeer [188]

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}\\\\
-------------------------------\\\\
x^2+y^2=25\implies (x-0)^2+(y-0)^2=5^2$

so notice above, the circle is centered at h,k or 0,0, the origin, and has a ratio of 5.

and y = 2, is just a horizontal line, check the picture below.

7 0

3 years ago

How do you factor 2x^3+5y^3

Pavel [41]

All you do is...
$\mathrm{Apply\:sum\:of\:cubes\:rule:\:}x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)$

$2x^3+5y^3=\left(\sqrt[3]{2}x+\sqrt[3]{5}y\right)\left(\left(\sqrt[3]{2}\right)^2x^2-\sqrt[3]{2}\sqrt[3]{5}xy+\left(\sqrt[3]{5}\right)^2y^2\right)$
$\left(\sqrt[3]{2}x+\sqrt[3]{5}y\right)\left(\left(\sqrt[3]{2}\right)^2x^2-\sqrt[3]{2}\sqrt[3]{5}xy+\left(\sqrt[3]{5}\right)^2y^2\right) \ \textgreater \ Refine$

$\left(\sqrt[3]{2}x+\sqrt[3]{5}y\right)\left(2^{\frac{2}{3}}x^2-\sqrt[3]{10}xy+5^{\frac{2}{3}}y^2\right)$

Hope this helps!

4 0

3 years ago