Answer:
Step-by-step explanation:
Answer:
29.16
Step-by-step explanation:
Degree is exponent, so 5th degree
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
t^2-5^2=(t-5)(t+5)
2nd one
complete square
take 1/2 of linear coefient and square it
-6/2=-3, (-3)^2=9
add that to both sides
x^2-6x+9=-8+9
x^2-6x+9=1
factor
(x-3)^2=1
sqrt
take neg and pos root
x-3=+/-1
add 3
x=3+/-1
x=3+1 or x=3-1
x=4 or 2
3rd option
Answer:
=>By the work energy relation:-
=>W = ∆KE
=>Ff.s = 1/2(M+m)v^2
=>µk x N x s = 1/2(M+m)v^2
=>µk x (M+m) x g x s = 1/2(M+m)v^2
=>v = √[2µkgs]
=>v = √[2 x 0.82 x 9.8 x 10.6]
=>v = 13.05 m/s
By the law of momentum conservation:-
=>Mu = (M+m)v
=>9230u = (9230+1250) x 13.05
=>u = 14.82 m/s
Step-by-step explanation:
Answer:
(-∞,∞)
(-∞,∞)
Step-by-step explanation:
When someone asks for the domain they're asking for all the possible x values of the equation. In this case there are no restrictions so x can equal any real number
When someone asks for the range they're asking for all the possible y values. There are no restrictions and therefore y can equal any real number
