Answer:
= 3f + 8
Step-by-step explanation:
Given that:
= 2/3[3f+12]+f
By simplifying:
2/3 will be multiplied inside the bracket as follows:
= 2/3*3f + 2/3*12 + f
By cancelling the terms with each other we get:
= 2f + 24/3 + f
By simplifying the fraction we get:
= 2f + 8 + f
Adding like terms
= 3f + 8
This is the simplified expression.
i hope it will help you!
The distance to Neptune is greater.
It is about 10 to the 3rd power (1,000) times greater.
xBar ± z * sx / sqrt(n)
where xBar is the sample
mean
z is the zscore for having
α% of the data in the tails, i.e., P( |Z| > z) = α
sx is the sample standard
deviation
n is the sample size
For sample size
calcualtions we need the following. The width of the interval, from one end
point to the center is:
z * sx / sqrt(n) =
w and solving for n gives:
<span> n = (z * sx / w) ^ 2 </span>
remember that n needs to
be an integer. Always take the ceiling, i.e., round up. If you round down then
the width of the interval will not be correct, it will be too wide. By rounding
up, the interval will be more narrow than asked for, but this is a good thing.
It means there is more precision in the estimate.
<span> here we have </span>
z = 2.05
w = 0.04 * 152 = 6.08
n = (z * sx / w) ^ 2 n =
(2.05 * 26 / 6.08)^2
n = 76.8506
Round of the answer since
n must be an integer.
<span>n = 77 </span>
Answer:
I believe the correct answer is f^-1 (x) = x - 3/2
Answer:
-15
Step-by-step explanation:
<u>Definition of absolute value: </u>
<em>Distance from zero on a number line. </em>
<em />
Imagine a number line with 0 in the middle of it. Now mark the number 3 on it. Also mark the <em>opposite </em>of 3, which is -3. What is the <u>distance</u> from zero to those 2 points? it's 3.
This is exactly like saying |3| = 3 and |-3| = 3
Even if the number inside absolute value is negative, it <em><u>simplifies</u></em> to the positive of the same number.
_______________________________
So let's talk about your problem.
-|-15|
> the absolute value simplifies to 15
-|-15| = - 15
So that ends up being your answer.
Hope this helps!!!!!!!
