<img src="https://tex.z-dn.net/?f=-12%20%2B%20%2812%29" id="TexFormula1" title="-12 + (12)" alt="-12 + (12)" align="absmiddle" c

All categories

Mashcka [7]

2 years ago

lass="latex-formula">

Mathematics

2 answers:

Harrizon [31]2 years ago

6 0

Answer:

Step-by-step explanation:

sladkih [1.3K]2 years ago

6 0

The answer is zero its like saying 12-12 =0

You might be interested in

C Campus Student

Alla [95]

52 is your answer

Hope this helps

4 0

3 years ago

The table shows the relationship between Megan’s earnings and the hours that she worked.

soldier1979 [14.2K]

Answer:

C.76

Step-by-step explanation:

2x= 19

x= 9.5

8x =?

8(9.5)= ?

76= ?

8 0

2 years ago

Graph -3.5 and -1.5 on the number line.

faust18 [17]

Answer:

ok i kow this hold on

Step-by-step explanation:

6 0

3 years ago

What is the answer to 2 + -1/3 =

Helga [31]

The answer is : 1:6 repeating

4 0

2 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago