Disregarding air friction, the distance traveled by an object due to gravity is : H = 0.5*g*t^2. g is the gravitational constant at the surface of earth.
g= 9.81 m/s^2
After 3 seconds, Distance = .5*9.81*9 = 44.15 meters traveled.
Since it was dropped from a height of 90 meters, the current height is 90 - 44.15 = (a) 45.85 meters
(b) It has to travel 90 meters to hit the ground . So we must find t
Using the same equation
t = (2*H/g)^.5
t = (2*90/g)^.5 = 4.28 seconds until it hits the ground
Answer:
Area of rectangle: 256
Area of triangle 1: 24
Area of triangle 2: 16
Area of triangle 3: 96
Area of trapezoid: 120
Step-by-step explanation:
I just did the question on the thing so Ik I'm right.
-The graph measures by twos. To get the area of the rectangle get the base times height of it. That would be 16x16=256.
-Get base (8) times height (6) of triangle 1 then divide by 2, remember to count the squares by 2 for finding all areas. The formula would be 1/2(b)(h) because dividing by 2 is the same as multiplying times 1/2. Plug it in and (8)(6)=48 then divide by 2 which equals 24.
-Same formula for triangle 2. Plug it in and (8)(4)=32 and divide by 2 and it equals 16.
-Same formula for triangle 3. Plugged in is (12)(16)=192 divide by 2 and it equals 96.
-To find the area of the trapezoid get your rectangle area (256) and subtract all the triangle areas. So 256 - 6 - 16 - 96 = 120.
-5n on both sides
M= -5n + p
3 is the answer to your question
