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Arada [10]
3 years ago
10

One batch of walnut muffins uses 1 1/3 cup of walnuts.How many cups of walnuts are needed to make 3 3/4 batches of muffins?

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0
The answer is 5 cups
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Pythagorean triples are specific combinations that occur frequently in right triangles and use only whole numbers. An example of
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The answer is D.) 6, 8, 10
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What is the distance between (-6, 2) and (8, 10) on a coordinate grid?
lawyer [7]

Answer:

The answer is 2(the square root of 65 )

Step-by-step explanation:

Plug ( -6, 2) and (8, 10) into the distance formula and solve.

Distance = the square root of ((x2 - x1)^2 + (y2 - y1)^2))

Distance = the square root of ((8 - -6)^2 + (10 - 2)^2))

Distance = the square root of (14^2 + 8^2)

Distance = the square root of (196 + 64)

Distance = the square root of 260 which can be simplified to 2(the square root of 64)

5 0
3 years ago
A school requires an entrance exam score that is in the top 3% of the population in order to be accepted. If an entrance exam ha
Troyanec [42]
The answer is letter C.) 603.40

The minimum required score can solved using the equation
<span>MRS = mean + (zscore)(SD)

where z score of 0.03 is 1.88

</span>MRS <span>= </span>500 + (1.88)(55)
MRS = <span>603.40

</span>

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>

3 0
2 years ago
If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12
Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta

\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x

\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}

\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta

\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x

\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}

\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}

\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}

\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}

Therefore, the expression reduces to

\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}

\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}

\;\;\;\;\;= \dfrac{49}{26}

5 0
2 years ago
Help me out, please. Thank you!!
andrezito [222]

Answer:

y=-2/3+3

Step-by-step explanation:

3 0
2 years ago
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