Question

Find the value of x. (Picture attached.)

Answer 1

Here, triangle AEN and ALG are similar.

We know that the ratio of corresponding sides of two similar triangles are equal. So,

$\frac{21}{42} =\frac{2x-9}{(2x-9)+(x+7)}\\\\\frac{1}{2} =\frac{2x-9}{3x-2}\\\\ 3x-2=4x-18\\\\-2+18=4x-3x\\\\16=x\\\\x=16$