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Margaret [11]
3 years ago
14

Please solve this i really need the help Y-2 = ½(X-3)

Mathematics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

(If solving for x) X = 2y-1

Step-by-step explanation:

Y-2 = 1/2(x-3)

Distributive property

Y-2 = 1/2x - 1.5

Addition property of equality

Y-0.5=1/2x

Multiplication property

2Y-1=X

Symmetric property

X = 2y-1

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3/3x + 1/(x + 4) = 10/7x

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Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

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{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

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(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

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