Sn=n/2 (2a1 +(n-1)d)
[s5= 5/2 (2a1 +(5-1)d) = 5a1+10d]
s6=3(2a1+5d) = 6a1+15d
s4=2(2a1+3d) = 4a1+6d
6a1+15d -(4a1+6d) = 5 -----(1)
s7=7/2(2a1+6d) =7a1+21d
6a1+15d + 7a1+21d = 21 -----(2)
(1) 2a1+9d=5 -----(3)
(2) 13a1+36d=21 ----(4)
(3)*4 ; 8a1+36d=20 ----(5)
(4)-(5) 5a1 = 1
so a1 = 1/5
(3) 2a1+9d=5
2(1/5)+9d = 5
9d = 5-2/5 =23/5
d = 23/45
so [s5= 5/2 (2a1 +(5-1)d) = 5a1+10d = 5(1/5) + 10(23/45) = 1 + 5.11 = 6.11 ]
i'm not sure about the answer but the process is correct
Answer:
24cm
Step-by-step explanation:
pi(4^2) = 50.26548246
This is the area of the circle
384pi / area of circle = 24cm
Answer:
-21
Step-by-step explanation:
Given:
h(x) = x − 1 - - - (1)
j(x) = −4x - - - - - (2)
h[j(5)]
j(5) = - 4(5) = - 20
g(-20) = - 20 - 1
Hence,
h[j(5)] = - 21
Answer:
Area = 77.1
Step-by-step explanation:
The are of a right triangle is

our base and height are 6 for both triangles, so we shall find the area of one of the triangles...

multiply this by 2

Now find the area of the whole circle

our radius is 6, therefore:

Finally, subtract the area of the two triangles from the total are of the circle. The difference left over is our answer

Answer:

Step-by-step explanation:
Since the numerator are like terms so you just add them together and leave the denominator the same.
