Answer:
The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 50 - 1 = 49
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0096
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.1 - 1.1 = 4
The upper end of the interval is the sample mean added to M. So it is 5.1 + 1.1 = 6.2.
The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).
3 feet = 36 inches 4 yards = 13 feet 12 feet = 4 yards
3w +2 =7w
-3w -3w
2=4w
Divide each side by 4
1/2=w
Check your answer:
3 (1/2) + 2 = 7 (1/2)
(3/2) + (4/2) = (7/2)
(7/2) = (7/2)
Hope this helps.
The length of the line is the difference between the endpoints of the line
The length of each line to the nearest fourth inch is 0.25 inch
<h3>How to measure the length of each line</h3>
The length of the horizontal line is given as:
Length = 2 inches
This is calculated as:
Length = 3 inches - 1 inch
Length = 2 inches
8 lines are to be drawn between the 1 inch and 3 inches point.
So, the length (l) of each line is:

Simplify the fraction

Divide

Hence, the length of each line to the nearest fourth inch is 0.25 inch
Read more about line measurements at:
brainly.com/question/14366932
Answer:
3 down, 4 up
Step-by-step explanation:
-3 is the X line, which starts on 0, if you subtract 3, or add -3, you would have to go down, 3 down. 4 is on the Y line, so you add, go left to add on the Y line, 4 up.
Always start with you X coordinate. Here is a tip to help you (X, Y)