Answer:
8
Step-by-step explanation:
Let's start with a simple fact: two sides of an isosceles triangle must be equal. Let's suppose the missing side is 4
That would mean that 4 + 4 equals 8. You must pick a side that exceeds 8, but you loose the property of 2 sides need to be equal.
So the answer has to be 8. The final size of the sides is 4 8 and 8. 4 and 8 exceed the third side (8).
8 and 8 certainly exceed 4.
Answer:
Angle B is 45°
Step-by-step explanation:
Since a and b are both of length 20, this is an isosceles right triangle, and the angle opposite side b must be 45°.
Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²
Answer:
f(x) + g(x) = -2x^2 - 2x + 8
Step-by-step explanation:
Given: f(x) = 3x+5 and g(x) = -2x^2-5x+3
Find f(x) + g(x)
f(x) + g(x) = 3x + 5 + (-2x^2 - 5x + 3)
f(x) + g(x) = 5 + -2x^2 - 2x + 3
f(x) + g(x) = -2x^2 - 2x + 8
