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schepotkina [342]
3 years ago
8

Triangle FGH is graphed on the coordinate plane below.

Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

(x, y) right-arrow (negative x, negative y) ⇒ (x, y) → (-x, -y)

Step-by-step explanation:

Let us revise the rotation about the origin

  • If point (x, y) rotated about the origin by angle 90° counterclockwise (or 270° clockwise), then its image is (-y, x) . The rule is (x, y) → (-y, x)
  • If point (x, y) rotated about the origin by angle 180° counterclockwise ( or 180° clockwise), then its image is (-x, -y) . The rule is (x, y) → (-x, -y)
  • If point (x, y) rotated about the origin by angle 270° counterclockwise (90° clockwise), then its image is (y, -x) . The rule is (x, y) → (y, -x)

Let us solve the question

∵ The vertices of triangle FGH are (-6, -8), (-2, -3), (-4, -2)

∵ The figure is rotated 180° using the origin as the center of rotation

→ By using the 2nd rule above

∴ The vertices of its image are (6, 8), (2, 3), (4, 2)

∴ The rule is (x, y) → (-x, -y)

The coordinates of the vertices of the preimage compare to the coordinates of the vertices of the image do (x, y) right-arrow (negative x, negative y) ⇒ (x, y) → (-x, -y)

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Answer:

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Step-by-step explanation:

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