A = 30
B = 41
C = 70
A < B + C
30 < 41+70 ==> 30 < 111 (TRUE)
B < A + C ==>
41 < 30 + 70 ==> 41 < 100 (TRUE)
C < A+B
70 < 30 + 41 ==> 70 < 71 (TRUE)
Yes, can!
its actually 10 points
x^4 + 9x^3 + 15x^2 + 9x + 14
Split 15x^2 into 14x^2 + x^2
x^4 + 9x^3 + 14x^2 + x^2 + 9x + 14 factor as
x^2 [x^2 + 9x + 14 ] + 1 [ x^2 + 9x + 14 ] take out GCF
[ x^2 + 1 ] [ x^2 + 9x + 14 ]
[ x^2 + 1 ] [ x + 7 ] [ x + 2 ]
mark brainliest
Answer:
False
Step-by-step explanation:
If this number is larger than 6, then its square is larger than 36.
If x > 6, then x² > 36
The number is not larger than 6.therefore Its square is not larger than 36.
x ≤ 6; therefore, x² ≤ 36
-7 is < 6; however -7² > 36 as -7² = 49
The answer is 48 feet (D).
Explanation:
To solve this, you must think of the monument and its shadow and Adam and his shadow as a triangle, the person/object being the vertical leg, the shadows being the horizontal leg, and a line connecting them being the hypotenuse. Also, we can assume that these triangles are similar. First, we can set the scale to be 40/5 (the two shadows set a scale because the triangles are similar). Then, we can put x/6 (the actual things are similar, and the scale was established to be building/measurement). Next, we can set the two fractions equal to each other (40/5 = x/6) and solve. We can cross multiply to get 5x = 40 * 6. That goes to 5x = 240. Finally, we can divide by five on each side to get x = 48 feet (D).
82$ and 74$ since there is a variety of the same numbers
