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astra-53 [7]
3 years ago
10

Plz answer..........

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

2210.6 m^3

Step-by-step explanation:

Volume of a cylinder is \pi r^2h

V=(3.14)(8)^2(11)\\\\=(3.14)(64)(11)\\\\=2210.56

they want to the nearest tenth, so ≈ 2210.6

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Represent the following expressions as a power of the number a (a≠0): c ((a2)−2)5÷(a4a)3
s2008m [1.1K]

Answer:

1/a²⁷

Step-by-step explanation:

Given: $ \frac{((a^2)^{-2})^5}{a^4.a^3} $

We know that when the bases are same the powers can be added. i.,e.,

                                           (xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾

⇒ $ \frac{((a^2)^{-2})^5}{a^4.a^3} \implies \frac{(a^2)^{-10}}{a^7} $

$  \implies \frac{a^{-20}}{a^7} = a^{-20 - 7} = a^{-27} $

Also, $ \frac{x^a}{x^b} = x^{a - b} $

This is nothing but, $ \frac{1}{a^{27}} $.

Note that $ a $ cannot be zero here. The condition is provided in the question as well.

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3 years ago
Which combination of numbers in this group has the highest value?
Anit [1.1K]
The answer would be <span>4*|-2| </span>
3 0
3 years ago
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We just saw an example of "Survival of the fittest" with the rabbits that survived. We often use this as an expression to descri
GarryVolchara [31]

Answer:

If only the fittest survive in certain enviorments other animals have to evolve to live in different places

Step-by-step explanation:

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2 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

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  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

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3 years ago
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iragen [17]
Correct - wrong    percentage
-------------------- = ---------------
       wrong                100
68 - 60      x
--------- = ----
   60       100
 8       x
---- = ----
<span>60    100
</span>800    60x
----- = ----
 60     60
13.3% = x
5 0
3 years ago
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