A geostationary orbit can be achieved only at an altitude very close to 35,786 km (22,236 mi) and directly above the equator. This equates to an orbital velocity of 3.07 km/s (1.91 mi/s) and an orbital period of 1,436 minutes, which equates to almost exactly one sidereal day (23.934461223 hours).
Answer:
Explanation:
Sexual reproduction is when a male and female have sexual inter course an and produce sex cells. A males sex cell is the sperm and the Females sex cell is the ova or egg cells.
Answer:
The height from which the ball was thrown is 18.82 m
Explanation:
Given;
horizontal velocity of the ball, vi = 27.0 m/s
horizontal distance of the ball, d = 53.0 m
Apply kinematic equation, to determine the time taken for the ball to make a horizontal distance of 53.0 m.
d = vt
t = d/v
t = 53/27
t = 1.96 seconds
This time is equal to the time the ball spent in air before hitting the ground.
The vertical distance at this time, is the height from which the ball was thrown, and it is calculated as;
h = vt + ¹/₂gt²
v is vertical velocity, = 0
g is acceleration due to gravity
h = ¹/₂ x 9.8 x (1.96)²
h = 18.82 m
Therefore, the height from which the ball was thrown is 18.82 m
Answer:
120 N
Explanation:
F=ma therefore 60kg times 2m/s^2 is 120 N