<span>6∙7-3^2∙9+4^3
= 42 - 9*9 + 64
= 42 - 81 + 64
= 25
answer
25</span>
We need to solve x+2y=11 for x
Let's start by adding -2y to both sides
x+2y -2y = 11-2y
x= -2y+11
Now substitute -2y+11 for x in x-2y =-1
x-2y=-1
-2y+11-2y=-1
-4y+11=-1
Add -11 to both sides
-4y+11-11=-1-11
-4y=-12
Divide both sides by -4
-4y/-4 = -12/-4
y= 3
Substitute 3 for y in x=-2y+11
x= -2y+11
x = (-2)(3)+11
x=-6+11
x=5
The answer is x=5 and y=3
(5,3)
I hope that's help:)
Answer:
n must be greater than 5 for the product to be greater than 10.
Step-by-step explanation:
10 times 2/5 = 4 (no)
10 times 6/5 = 12 (yes)
10 times 5/5 = 10 (no)
Answer:
5
Step-by-step explanation:
Pythagoras's theorem dictates that a squared + b squared = c squared when talking about sides on right angled triangles with a and b being flat sides and c being the hypotenuse which gives us the forumula below
3 squared + 4 squared = 25 route 25 = 5
Answer:
9.34%
Step-by-step explanation:
p = 4%, or 0.04
n = Sample size = 667
u = Expected value = n * p = 667 * 0.04 = 26.68
SD = Standard deviation =
= 5.06
Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?
This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35
Since,
Z = (X - u) / SD
We have;
Z = (33.35 - 26.68) / 5.06
Z = 1.32
From the Z-table, the p-value of 1.32 is 0.9066
1 - 0.9066 = 0.0934, or 9.34%
Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.