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Scilla [17]
3 years ago
9

Triangle E F G is shown. Which statements regarding Triangle E F G are true? Select three options. E F + F G greater-than E G E

G + F G greater-than E F E G minus F G less-than E F E F minus F G greater-than E G E G + E F less-than F G
Mathematics
2 answers:
Eddi Din [679]3 years ago
8 0

Answer:

1) E F + F G greater-than E G

2) E G + F G greater-than E F

3) E G minus F G less-than E F

Step-by-step explanation:

I got it right on edg

Leokris [45]3 years ago
4 0

Answer:

options 1 ( E F + F G greater-than E G ), 2 (E G + F G greater-than E F ) and 5 ( E G + E F less-than F G ) are true.

Step-by-step explanation:

Given triangle EFG.

In each tirangle with sides lengths a, b and c, we always have

a+b>c\\ \\a+c>b\\ \\b+c>a

In triangle EFG:

  • EF+FG>EG;
  • EG+GF>EF;
  • FE+EG>FG.

So, options 1 ( E F + F G greater-than E G ), 2 (E G + F G greater-than E F ) and 5 ( E G + E F less-than F G ) are true.

Options 3 and 4 are false.

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Need to know angle 1, angle 2, angle 3
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Answer: Step-by-step explanation:

angle 1=41°

angle 2=angle 1=41°

angle 3=180-2×41=98

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3 years ago
Andrea and sula ran a race on a track that was 100 meters long.When andrea crossed the finish line sula was exactly 5 meters beh
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Andrea will be at 95 meters and Sula would win I think.
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A 12 foot ladder is leaning against the side of a building. The top of the ladder reaches 10 feet up the side of the building. A
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3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
What is the slope of the the line shown below?​
ollegr [7]

Answer:

The answer is A. -2/7

Step-by-step explanation:

5 0
3 years ago
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