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Scilla [17]
4 years ago
9

Triangle E F G is shown. Which statements regarding Triangle E F G are true? Select three options. E F + F G greater-than E G E

G + F G greater-than E F E G minus F G less-than E F E F minus F G greater-than E G E G + E F less-than F G
Mathematics
2 answers:
Eddi Din [679]4 years ago
8 0

Answer:

1) E F + F G greater-than E G

2) E G + F G greater-than E F

3) E G minus F G less-than E F

Step-by-step explanation:

I got it right on edg

Leokris [45]4 years ago
4 0

Answer:

options 1 ( E F + F G greater-than E G ), 2 (E G + F G greater-than E F ) and 5 ( E G + E F less-than F G ) are true.

Step-by-step explanation:

Given triangle EFG.

In each tirangle with sides lengths a, b and c, we always have

a+b>c\\ \\a+c>b\\ \\b+c>a

In triangle EFG:

  • EF+FG>EG;
  • EG+GF>EF;
  • FE+EG>FG.

So, options 1 ( E F + F G greater-than E G ), 2 (E G + F G greater-than E F ) and 5 ( E G + E F less-than F G ) are true.

Options 3 and 4 are false.

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All real numbers

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3 years ago
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

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3 years ago
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