2 years ago

Please help with math 30 points

Mathematics

1 answer:

AlladinOne [14]2 years ago

7 0

Y=|x+7|-9

Im not sure how to explain this sorry

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what's the difference between (-4)^-3 and -4^-3. basically what's the difference when there's parenthesis for the base number?

NNADVOKAT [17]

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-4^-3 = $\frac{1}{-64} or -0.015625$

Basically in this situation there is no difference whether parenthesis are used or not.

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2 years ago

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earnstyle [38]

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3 years ago

Find the second derivative of 2x^3-3y^2=8

Umnica [9.8K]

Answer:

$\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

Step-by-step explanation:

Find the first implicit derivative using implicit differentiation

$2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}$

Use the substitution of dy/dx to find the second derivative (d²y/dx²)

$\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$