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3 years ago

7.1 Pythagorean Theorem

Mathematics

1 answer:

nlexa [21]3 years ago

7 0

Lmk if u have any questions :)

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Can somebody help please.

Shtirlitz [24]

The standard form will be:

a. 3.15

b. 3.015

<h3>How to calculate the value?</h3>

It should be noted that the question is simply about converting the expanded form to standard form.

This will be:

(3 × 1) + (1 × 0.1) + (5 × 0.01)

= 3 + 0.1 + 0.05

= 3.15

b. (3 × 1) + (1 × 0.01) + (5 × 0.001)

= 3 + 0.01 + 0.005

= 3.015

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

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1 year ago

33.63 miles in 3 hours what is the speed in miles per hour

Sveta_85 [38]

11.21 miles because you divide 33.63 by 3 and you'll get your answer.

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3 years ago

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Please answer ive been waiting half hour

Oksana_A [137]

I’m pretty sure it’s plant

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3 years ago

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8.3 as a mixed number

Alik [6]

Step-by-step explanation:

8.3 = 8+ 0.3

= 8 + 3/10

= 8 3/10

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3 years ago

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A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

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3 years ago

7.1 Pythagorean Theorem ​

7.1 Pythagorean Theorem